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gladu [14]
3 years ago
7

What mass of natural gas (ch4) must you burn to emit 272 kj of heat?

Chemistry
1 answer:
balandron [24]3 years ago
7 0
CH4 + 2 O2 ---> CO2 + 2 H2O Q = 891,6 kJ / mol CH4

1 mol CH4 = 16 g

16 g ---- 891,6 kJ
x g ----- 272 kJ

x = 272 kJ × 16 g / 891,6 kJ = 4,88 g

You must burn 4,88 g of CH4.

:-) ;-)
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3 years ago
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hram777 [196]

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                                         pH  =  pKa  +  log [A⁻] / [HA]   -------- (1)

Solution:

Convert Ka into pKa,

                                         pKa  =  -log Ka

                                         pKa  =  -log 1.37 × 10⁻⁴

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                   log [lactate] / [lactic acid]  =  4.29 - 3.863

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Taking Anti log,

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4 years ago
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