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2 years ago

What mass of natural gas (ch4) must you burn to emit 272 kj of heat?

1 answer:

7 0

CH4 + 2 O2 ---> CO2 + 2 H2O Q = 891,6 kJ / mol CH4

1 mol CH4 = 16 g

16 g ---- 891,6 kJ
x g ----- 272 kJ

x = 272 kJ × 16 g / 891,6 kJ = 4,88 g

You must burn 4,88 g of CH4.

:-) ;-)

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If we examine after 3 days, there will be a decrease in the concentration of NaCl and a decrease in the water level.

Explanation:

If we inspect the following 3 days, there'll be a reduction inside the convergence of NaCl and a lessening inside the water level. This focus is diminished in 2 different ways, by expanding the solute or diminishing the water.

Expanding the solute will build the arrangement's focus. This should be possible by just including a greater amount of your compound into the arrangement and dissolving it. It may not help in case you're utilizing a watery arrangement that is as of now disintegrated in water.

You can utilize a procedure called dialysis to diminish the water in an solution.

Spot your answer in a dialysis pack that is shaped of semipermeable substance. Presently place the pack in an answer which has a high grouping of a particle. Accordingly, water will be kept concealed separately from the pack through the semi-penetrable film by hurrying out of the sack to the arrangement.

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2 years ago

In what circumstances do scientists use observational research and opinion based research?

Zielflug [23.3K]

The circumstances when scientists use observational research and opinion based research is when they include animals or things that cannot control for a product. Observational research is a type of research which only observes ongoing behavior and studies about it and the results only rely on the behavior observed.

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2 years ago

How many moles of disulfur decafluoride are present in 3.99 x 104 molecules of this compound? moles

arsen [322]

Answer: The number of moles of disulfur decafluoride is $6.62\times 10^{-20}$

Explanation:

We are given:

Number of disulfur decafluoride molecules = $3.99\times 10^4$

According to mole concept:

$6.022\times 10^{23}$ number of molecules are contained in 1 mole of a compound.

So, $3.99\times 10^4$ number of molecules will be contained in = $\frac{1mol}{6.022\times 10^{23}}\times 3.99\times 10^{4}=6.62\times 10^{-20}mol$ of disulfur decafluoride.

Hence, the number of moles of disulfur decafluoride is $6.62\times 10^{-20}$

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3 years ago

You can practice converting between the mass of a solution and mass of solute when the mass percent concentration of a solution

vfiekz [6]

Answer:

450. g of 0.173 % KCN solution contains 779 mg of KCN.

Explanation:

Mass of the solution = m

Mass of the KCN in solution = 779 mg

Mass by mass percentage of KCN solution = 0.173%

$(m/m)\%=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 100$

$0.173\%=\frac{779 mg}{m}\times 100$

$m=\frac{779 mg}{0.173}\times 100= 450,289 mg$

1 mg = 0.001 g

m = 450,289 mg × 0.001 g = 450.289 mg ≈ 450. g

450. g of 0.173 % KCN solution contains 779 mg of KCN.

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3 years ago

A certain gas is present in a 13.0 l cylinder at 4.0 atm pressure. if the pressure is increased to 8.0 atm , the volume of the g

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Boyle's Law is k = PV so Initial k = 13.0 L x 4.0 atm = 52 L atm Final kf = 6.5 L x 8 atm = 52 L atm The gas obeys Boyle's Law The answer with two significant figures separated by a comma is k = 52, kf = 52.

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3 years ago

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