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Wittaler [7]
2 years ago
12

How to calculate atomic mass of sodium ?(in process)​

Chemistry
1 answer:
Vinvika [58]2 years ago
7 0

Answer:

Atomic mass of Sodium is 22.9897 u. Note that, each element may contain more isotopes, therefore this resulting atomic mass is calculated from naturally-occuring isotopes and their abundance. The unit of measure for mass is the atomic mass unit (amu). One atomic mass unit is equal to 1.66 x 10 -24 grams.

Explanation:

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In the endothermic reaction because heat is absorbed , the products have a higher heat.
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3 years ago
What could be the fourth quantum number of a 1s^2 electron be?
Bumek [7]

The forth quantum number is Spin quantum number and the value of Spin Quantum Number of 1s² will be +1/2. Therefore, the correct option is (B) option

<h3>What is Spin Quantum Number ?</h3>

It describes the orientation of the electron spin (rotation) in space.

In the given case of 1s² configuration,

since, the Quantum numbers are known as:

  • Principal quantum number (n) which cannot be zero.

       The allowed values of n are therefore 1, 2, 3, 4, and so on.

  • Angular quantum number (l) is able to be any integer between 0  

       and n-1.

       Therefore, for example, If n = 1, l will be 0,

                                                If n = 2, l can be either 0 or 1.

  • Magnetic quantum number (m) is able to be any integer between -l and +l.    

       Therefore, for example, If l = 3, m can be either -3 to +3.

  • Spin Quantum Number (ms): Ms = +½ or -½  accounts for the orientation of the spin axis of an electron as it is able to spin in only one of two directions.

Thus, since the fourth quantum number is Ms, spin, we infer that the answer is (B) option ie, Ms = +1/2 because it represents the positive spin on 1s².

Learn more about Quantum Number Here ;

brainly.com/question/15325270

#SPJ1

6 0
2 years ago
2. A quantity of 1.922g of methanol (CH3OH) was burned in a constant-volume
Cerrena [4.2K]
Mass of methanol (CH3OH) = 1.922 g
Change in Temperature (t) = 4.20°C
Heat capacity of the bomb plus water = 10.4 KJ/oC
The heat absorbed by the bomb and water is equal to the product of the heat capacity and the temperature change.
Let’s assume that no heat is lost to the surroundings. First, let’s calculate the heat changes in the calorimeter. This is calculated using the formula shown below:
qcal = Ccalt
Where, qcal = heat of reaction
Ccal = heat capacity of calorimeter
t = change in temperature of the sample
Now, let’s calculate qcal:
qcal = (10.4 kJ/°C)(4.20°C)
= 43.68 kJ
Always qsys = qcal + qrxn = 0,
qrxn = -43.68 kJ
The heat change of the reaction is - 43.68 kJ which is the heat released by the combustion of 1.922 g of CH3OH. Therefore, the conversion factor is:
5 0
2 years ago
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