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3 years ago

13

Suppose a train car moving down a track at 10 m/s collides with another train car that is moving. Explain how momentum is conser

ved after the collision.

1 answer:

lora16 [44]3 years ago

5 0

The two trains will collide pushing each other back slightly. The momentum will transfer from one train to another pushing each other back

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Electrons have _______ charge.

Nikolay [14]

Answer:Electrons have negative charge.

Explanation:Electrons are designated to be the carriers of negative charge. The assignment of negative and positive to electrons and protons respectively can be attributed to Benjamin Franklin. He could have easily reversed this designation. Like all charged particles, negative charges create electric fields around them.

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4 years ago

What is the specially shaped crystal that can bent light?

suter [353]

Answer:

The answer is a prism

Hope it helps...............

4 0

3 years ago

Assume that the pictured magnet is being moved into the solenoid. If the polarity of the magnet is reversed and then moved into

KonstantinChe [14]

Answer:

The direction of induced emf is revered and hence the direction of the induced current.

Explanation:

If the polarity of the magnet is reversed, the direction if the field lines through the solenoid is also reversed, which according to Faraday's law means

$\varepsilon =N\dfrac{d\Phi}{dt} \rightarrow -N\dfrac{d\Phi}{dt}$

in other words, the direction of the magnetic flux is revered, and therefore, the direction of the induced emf is also revered.

Furthermore, according to Ohm's law

$I = \dfrac{\varepsilon}{R}$

which tells us that if the induced emf changes sign <em>(is reversed)</em>

$I = -\dfrac{\varepsilon}{R}$

the direction of the induced current is also reversed.

7 0

3 years ago

A stone is thrown horizontally from 2.4m above the ground at 35m/s. The wall is 14m away and 1m high.At what height the stone wi

KIM [24]

The stone reaches the wall at a height of <u>1.62 m</u>.

The stone lands at a point <u>24.5 m</u> from the point of projection.

The stone is projected horizontally with a velocity u at a height <em>h</em> from the ground. The wall is located at a distance <em>x</em> from the point of projection. The stone takes a time <em>t</em> to reach the wall and in the same time the stone falls a vertical distance <em>y</em>.

The horizontal distance <em>x</em> is traveled with a constant velocity <em>u</em>.

$x=ut$

Calculate the time taken <em>t</em>.

$t=\frac{x}{u} \\ =\frac{14m}{35 m/s} \\ =0.40s$

The stone's initial vertical velocity is zero. It falls through a distance <em>y</em> in the time <em>t</em> under the action of acceleration due to gravity <em>g</em>.

$y=\frac{1}{2} gt^2\\ \frac{1}{2} (9.81m/s^2)(0.40s)^2\\ =0.784m$

The height <em>h₁ </em>of the stone above the ground when it reaches the wall is given by,

$h_1=h-y\\ =(2.4m)-(0.784m)\\ =1.616m=1.62m$

When the stone reaches the wall, its height from the ground is <u>1.62m.</u>

The stone thus crosses over the wall, since the height of the wall is 1 m. It reaches the ground at a distance <em>R</em> from the point of projection. If the time taken by the stone to reach the ground is <em>t₁, </em>then,

$h=\frac{1}{2} gt_1^2$

Calculate the time taken by the stone to reach the ground.

$t_1=\sqrt{\frac{2h}{g} } \\=\sqrt{\frac{2(2.4m)}{9.81m/s^2} } \\ =0.699 s$

The horizontal distance traveled by the stone is given by,

$R=ut_1 \\ =(35m/s)(0.699s)\\ =24.5m$

The stone lands at point 24.5 m from the point of projection and 10.5 m from the wall.

3 0

3 years ago

Calculate the speed of an 8.0 × 104 kg airliner with a kinetic energy of 1.1 × 109 J.

Mazyrski [523]

KE = ½mv²
<span>1.1 x 10^9 = ½ x 8 x 10^4 v²
v² = 2.75 x 10^4
v ≈ 165.8 m/s</span>

5 0

3 years ago