Answer:
Avogadro's law.
Explanation:
Avogadro’s law states that, equal volumes of all gases at the same temperature and pressure contain the same number of molecules.
Mathematically,
V n
V = Kn where V = volume in cm3, dm3, ml or L; n = number of moles of gas;
K = mathematical constant.
The ideal gas equation is a combination of Boyle's law, Charles' law and Avogadro’s law.
V 1/P at constant temperature (Boyle’s law)
V T at constant pressure ( Charles’law)
V n at constant temperature and pressure ( Avogadro’s law )
Combining the equations yields,
V nT/P
Introducing a constant,
V = nRT/P
PV = nRT
Where P = pressure in atm, Pa, torr, mmHg or Nm-2; V = volume in cm3, dm3, ml or L; T = temperature in Kelvin; n = number of moles of gas in mol; R = molar gas constant = 0.082 dm3atmK-1mol-1
Answer:
t = 16.5s
Explanation:
Given parameters:
Acceleration = 3.1m/s²
Initial velocity = 0m/s
Final velocity = 51m/s
Unknown:
Time taken = ?
Solution:
To solve this problem we need to reiterate that acceleration is the rate of change of velocity with time.
So;
Acceleration = 
v is the final velocity
u is the initial velocity
t is the time taken
So;
3.1 = 
3.1t = 51
t = 16.5s
Answer:
Radio Wave
Micro Wave
Explanation:
Electromagnetic waves are transverse waves composed by the perpendicular oscillating electric and magnetic fields.
EM waves have both Electrical and magnetic features.
they travel in the velocity of light (3*10⁸ ms⁻¹)
Electromagnetic spectrum is obtained according to their wave length and the frequency. Due to wave length range it's categorized. Here is the decreasing order of wave length and increasing order of different wave types in electromagnetic spectrum
- Radio Wave
- Micro Wave
- IR wave
- Light Wave
- UV rays
- X rays
- Gamma rays
- Cosmic rays
Answer:
0.29 m
Explanation:
9 mm = 0.009 m in diameter
Cross-sectional area 
Let the tensile modulus of Nickel 
.
The elongation of the rod can be calculated using the following formula:
Answer:
O C. Light energy
Explanation:
it conducts energy in it and is an energy itself.
