Answer:
The answer to this is
The column of water in meters that can be supported by standard atmospheric pressure is 10.336 meters
Explanation:
To solve this we first list out the variables thus
Density of the water = 1.00 g/mL =1000 kg/m³
density of mercury = 13.6 g/mL = 13600 kg/m³
Standard atmospheric pressure = 760 mmHg or 101.325 kilopascals
Therefore from the equation for denstity we have
Density = mass/volume
Pressure = Force/Area and for a column of water, pressure = Density × gravity×height
Therefore where standard atmospheric pressure = 760 mmHg we have for Standard tmospheric pressure= 13600 kg/m³ × 9.81 m/s² × 0.76 m = 101396.16 Pa
This value of pressure should be supported by the column of water as follows
Pressure = 101396.16 Pa = kg/m³×9.81 m/s² ×h
∴ 
= 10.336 meters
The column of water in meters that can be supported by standard atmospheric pressure is 10.336 meters
Answer:
0.075 moles of product formed.
Explanation:
Given data:
Number of moles of oxygen = 0.30 mol
Number of moles of oxygen = 0.15 mol
Number of moles of product formed = ?
Solution:
Chemical equation:
4Na + O₂ → 2Na₂O
Now we will compare the moles of Na₂O with oxygen and sodium.
Na : Na₂O
4 : 2
0.15 : 2/4×0.15 = 0.075 mol
O₂ : Na₂O
1 : 2
0.30 : 2/1×0.30 = 0.6 mol
Less number of moles of Na₂O are produced by sodium thus it will limit the yield of Na₂O and act as limiting reactant while oxygen is in excess.
Answer:
: 0.5 atm and 
: 1 atm
Explanation:
In order to calculate the partial pressure for each gas , all you need to do is multiply the mole fraction of each gas with the total pressure.
It is given that 
= 1.5 atm
The mole fraction of each gas can be calculated in the following way:
= moles of ÷ total moles present = 
= moles of ÷ total moles present = 
Partial pressure of : 1.5 × = 0.5 atm
Partial pressure of : 1.5 × = 1 atm
Hope that answers the question, have a great day!
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