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gladu [14]
3 years ago
5

Which statement is true?

Chemistry
2 answers:
marin [14]3 years ago
8 0

your answer is c because rocks are NOT ALL THE TIME MADE WITH JUST ONE MINERAL

mihalych1998 [28]3 years ago
3 0
B. Most rocks are composed of single mineral
You might be interested in
Question 9 Multiple Choice Worth 4 points)
Rufina [12.5K]

Answer:

A

Explanation:

Would you base your career options using science?

Would you base your moral behavior on science? Science is notorious for not being able to answer moral questions.

Would you base the "meaning of life" on science? The meaning of life is hardly a question that the periodic table could answer.

The only option left is plant growth which science could answer.

4 0
3 years ago
Read 2 more answers
Hey please answer this thanks.
Aleks04 [339]

Explanation:

Percentage composition of oxygen = (80/134) * 100% = 59.7%.

6 0
3 years ago
HELP. NO FAKE ANSWERS. I WILL REPORT. I AM CONFUSED AND NEED HELP. FILL IN THE NOT FILLED BOXES POR FAVOR.
SCORPION-xisa [38]
Question #1
Potasium hydroxide (known)
 volume used is 25 ml 
Molarity (concentration) = 0.150 M
Moles of KOH used 
           0.150 × 25/1000 = 0.00375 moles
Sulfuric acid (H2SO4) 
volume used = 15.0 ml
unknown concentration
The equation for the reaction is
2KOH (aq)+ H2SO4(aq) = K2SO4(aq) + 2H2O(l) 
Thus, the Mole ratio of KOH to H2SO4 is 2:1
Therefore, moles of H2SO4 used will be;
      0.00375 × 1/2 = 0.001875 moles
Acid (sulfuric acid)  concentration
    0.001875 moles × 1000/15  
        = 0.125 M

Question #2
Hydrogen bromide (acid)
Volume used = 30 ml
Concentration is 0.250 M
Moles of HBr used;
      0.25 × 30/1000
        =  0.0075 moles 
Sodium Hydroxide (base)
Volume used 20 ml 
Concentration (unknown)
The equation for the reaction is 
NaOH + HBr = NaBr + H2O
The mole ratio of NaOH : HBr   is 1 : 1
Therefore, moles of NaOH used;
                 = 0.0075 moles
NaOH concentration will be 
       = 0.0075 moles × 1000/20
       = 0.375 M

7 0
3 years ago
A solution of rubbing alcohol is 68.6 % (v/v) isopropanol in water. How many milliliters of isopropanol are in a 88.2 mL sample
KonstantinChe [14]


From the information given, the total volume of  rubbing alcohol is 88.2 ml

68.6 % of this volume is isopropanol. 

We will assume 88.2 ml represents 100% volume, so the volume of water will be 31.4 %

The volume of isopropanol is

68.6/100 x 88.2 → 0.686 × 88.2 = 60.505 ml

The volume of isopropanol is 60.5 ml.

Volume of water will be 88.20 - 60.5 = 27.7 ml

(27.7 / 88.2 × 100 = 31.4% )

Adding 60.5 ml of isopropanol to 27.7 ml of water to make up 88.2 ml will give 68.6 % v/v isopropanol to water  solution.



8 0
4 years ago
How many O2 molecules react with 47 CH4 molecules according to the preceding equation CH4 + O2 → CO2 + H2O
natka813 [3]
I think 93.71 mol.
You need to use stochio

8 0
3 years ago
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