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gladu [14]
3 years ago
5

Which statement is true?

Chemistry
2 answers:
marin [14]3 years ago
8 0

your answer is c because rocks are NOT ALL THE TIME MADE WITH JUST ONE MINERAL

mihalych1998 [28]3 years ago
3 0
B. Most rocks are composed of single mineral
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Read 2 more answers
1 - 2Na + O2 ➔ Na2O Balanced Not Balanced
Mrrafil [7]

Answer:

1 not

2 not

3 not

4 balanced

5 not

6 not

7 balanced

Explanation:

the amount of elements must be equal in the reactant and products

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I Need Help!!! 50 POINTS AND BRAINLIEST!!! Fill out the study guide ASAP!!!
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5. Answer The energy associated with an object's motion is called kinetic energy. A speeding bullet, a walking person, and electromagnetic radiation like light all have kinetic energy. Another example of kinetic energy is the energy associated with the constant, random bouncing of atoms or molecules.

6.Answer is solid

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7. Answer Water behaves differently to most other substances because, in its solid state (ice), its particles are less densely packed than in its liquid state. This is why ice floats.

8. Answer 212 degrees F.

Sea Level: Water boils at 212 degrees F. and simmers at 190 degrees F.

9. Answer When an object is heated the motion of the particles increases as the particles become more energetic. If it is cooled the motion of the particles decreases as they lose energy.

10. Answer CHEMISTRY TERM                            PHASE CHANGE

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4 0
3 years ago
Which is heavier? A pound of cotton candy or a pound of marbles
Ugo [173]
Answer: both are equal


They weighed the same because they both a pound
6 0
3 years ago
Read 2 more answers
In the coal-gasification process, carbon monoxide is converted to carbon dioxide via the following reaction: CO (g) + H2O (g) ⇌
Oksana_A [137]

Answer: Equilibrium constant is 0.70.

Explanation:

Initial moles of  CO = 0.35 mole

Volume of container = 1 L

Initial concentration of CO=\frac{moles}{volume}=\frac{0.35moles}{1L}=0.35M

Initial moles of  H_2O = 0.40 mole

Volume of container = 1 L

Initial concentration of H_2O=\frac{moles}{volume}=\frac{0.40moles}{1L}=0.40M

equilibrium concentration of CO=\frac{moles}{volume}=\frac{0.18moles}{1L}=0.18M [/tex]

The given balanced equilibrium reaction is,

                            CO(g)+H_2O(g)\rightleftharpoons CO_2(g)+H_2(g)

Initial conc.            0.35 M       0.40M       0     0

At eqm. conc.    (0.35-x) M   (0.40-x) M   (x) M    (x) M

The expression for equilibrium constant for this reaction will be,

K_c=\frac{[CO_2]\times [H_2O]}{[CO]\times [H_2O]}

K_c=\frac{x\times x}{(0.40-x)(0.35-x)}

we are given : (0.35-x)= 0.18

x = 0.17

Now put all the given values in this expression, we get :

K_c=\frac{0.17\times 0.17}{(0.40-0.17)(0.35-0.17)}

K_c=0.70

Thus the value of the equilibrium constant is 0.70.

5 0
3 years ago
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