H ( x ) = - 6 + x
m = 1 ( the slope )
b = - 6 ( y - intercept )
x - intercept:
0 = - 6 + x
x = 6
The graph is going through Quadrants: I, II and IV.
Answer:
B ) Quadrant II, because the slope is positive and y-intercept is negative.
Hey there!
⇒ Use the vertex as the middle letter, and the point from each side (<ABC or <CBA)
⇒ Use the vertex only (<B)
⇒ Use a number (<1)
- Classify angles according to their measure.
⇒ Acute angle: less than 90°
⇒ Right angle: exactly 90°
⇒ Obtuse angle: between 90° and 180°
⇒ Straight angle: exactly 180°
Thank you,
Eddie
See the attachment for a visual!
Answer: 62
Step-by-step explanation: In the red empty spot, the #5 would go there and in the blue spot the #6 would go there. 8x2=16 and 16+16= 32: t=This is for the to rectangle shapes on both sides. Now for the square in the middle, since the red spot is 5 and the blue is 6, 5x6= 30. So, 30+32=62.
Answer:
graph B
Step-by-step explanation:
Given
3y - 5x < - 6
Since the inequality is < then the line must be broken
If ≤ then line would be solid
The only possible graphs are B and D
Choose a test point in the shaded region of each graph and check validity
graph B (2, 0) ← substitute into left side of inequality
0 - 5(2) = 0 - 10 = - 10 < - 6 ← this is valid
graph D (0, 0 ) ← substitute into left side of inequality
0 - 0 = 0 > - 6 ← this is not valid
Hence graph B is the correct graph