Answer:
2Rb(s) + Sr^+(aq) → 2Rb^+ (aq) + Sr(s)
Explanation:
Rubidium has a more negative reduction potential (-2.98 V) compared to strontium (-2.89 V).
Hence, in a redox reaction involving rubidium and strontium, rubidium will be oxidized while strontium is reduced.
The balanced redox reaction equation is obtained from;
Oxidation half equation;
2Rb(s) ---->2Rb^+(aq) + 2e
Reduction half equation;
Sr^2+(aq) + 2e ----> Sr(s)
Overall reaction equation;
2Rb(s) + Sr^+(aq) → 2Rb^+ (aq) + Sr(s)
<span>It was Rutherford who discovered that the positive charge part of the atom.
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<span>A. insoluble solids in water
</span><span>C. solids of different sizes</span>
Answer:
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Answer: NO2
Explanation:
N O
Divide each by its 25.93 74.07
mass number 14 16
2 4
Divide both by the 2 2
smaller (i.e. 2) 1 2
Therefore, the empirical formula = NO2
