All categories

2 years ago

How are passengers affected when a moving bus is stopped suddenly? Explain with reason.

Physics

1 answer:

Mademuasel [1]2 years ago

5 0

Answer:

When a moving bus stops suddenly, the passenger are pushed forward because of the inertia of the passengers. ... Because the lower part of the body comes to rest with the bus while the upper part tends to continue its motion due to inertia.

Explanation :

The passengers in a bus tend to fall backward when it starts suddenly due to inertia as the passengers tend to remain in the state of rest while the bus starts to move. When the bus stops suddenly, people fall forward because their inertia as they are in state of motion even when the bus has come to rest.

Hope this helps!! <3

Please mark as branliest

You might be interested in

A long uniform board weighs 52.8 N (10.6 lbs) rests on a support at its mid point. Two children weighing 206.0 N (41.2 lbs) and

natima [27]

The upward force exerted on the board by the support is 530.8 N.

<h3>Upward force exerted on the board by the support</h3>

The sum of the upward forces is equal to sum of downward forces;

total downward forces = 52.8 N + 206 N + 272 N = 530.8 N

downward force = upward force = 530.8 N

Thus, the upward force exerted on the board by the support is 530.8 N.

Learn more about upward force here: brainly.com/question/6080367

#SPJ1

8 0

2 years ago

A circuit is constructed with six resistors and two batteries as shown. the battery voltages are v1 = 18 v and v2 = 12 v. the po

VladimirAG [237]

Answer:

V4=9.197v

Explanation:

Given:

V1= 18v ,V2= 12v ,r1=r5=58ohms ,r2=r6=124ohms , r3=47ohms ,r4= 125ohms

V4= I4R4 = V2/(R4 + R5)×R4

V4= 12×125 /(125 + 58)

V4=1500/183 =9.197v

5 0

3 years ago

A 0.10 kg meter stick is held perpendicular to a vertical wall by a 2.5 mm string going from the wall to the far end of the stic

il63 [147K]

Explanation:

Sum of moments = 0 (Equilibrium)

T . cos (Q)*L = m*g*L/2

$cos Q = \frac{\sqrt{(2.5^2 - L^2) } }{2.5}$

$T*\frac{\sqrt{(2.5^2 - L^2) } }{2.5} * L = 0.1 *9.81*L/2$

$T = \frac{2.4525}{\sqrt{(2.5)^2 - L^2} }$

b) If the String is shorter the Q increases; hence, Cos Q decreases which in turn increases Tension in the string due to inverse relationship!

$T = \frac{1.962}{\sqrt{(2)^2 - L^2} }$

6 0

3 years ago

If the forces acting on an system produce a net force, what can we say about these forces

lutik1710 [3]

Net force refers to the (vector) sum of all the forces acting on something. It's a mathematical construction, so it's not a single identifiable force. The forces themselves are real, but the net force is not an actual force.

Hope this helps you out.

8 0

3 years ago

A 12.0kg microwave oven is pushed 14.0m up the sloping surface of a loading ramp inclined at an angle 37 degrees above the horiz

Semenov [28]

Answer:

Answered

Explanation:

a) What is the work done on the oven by the force F?

W = F * x

W = 120 N * (14.0 cos(37))

<<<< (x component)

W = 1341.71

b) $F_f=\mu_k N$

$F_f=0.25\times12\times9.8$

= 29.4 N

$W_f= F_f\times x$

$W_f= 29.0\times 14 cos(37)$

W_f= 328.72 J = 329 J

c) increase in the internal energy

U_2 = mgh

= 12*9.81*14sin(37)

= 991 J

d) the increase in oven's kinetic energy

U_1 + K_1 + W_other = U_2 + K_2

0 + 0 + (W_F - W_f ) = U_2 + K_2

1341.71 J - 329 J - 991 J = K_2

K_2 = 21.71 J

e) F - F_f = ma

(120N - 29.4N ) / 12.0kg = a

a = 7.55m/s^2

vf^2 = v0^2 + 2ax

vf^2 = 2(7.55m/s)(14.0m)

V_f = 14.5396m/s

K = 1/2(mv^2)

K = 1/2(12.0kg)(14.5396m/s)

K = 87.238J

4 0

3 years ago

How are passengers affected when a moving bus is stopped suddenly? Explain with reason.​

How are passengers affected when a moving bus is stopped suddenly? Explain with reason.