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2 years ago

6

You want to place a piece of glass tubing into a ruber stopper after the tubing has been fire polished and cooled. This is best

done by

1 answer:

igor_vitrenko [27]2 years ago

4 0

Answer:

All of the above

Explanation:

This is correct

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por favor es urgente!!!!!!!!.... 1 -¿cuántos átomos- gramos de cloro hay en 88,75 g de dicho elemento? 2-¿calcular los moles de

Mamont248 [21]

Answer:

don't understand your language

6 0

2 years ago

For a different reaction, the plot of the reciprocal of concentration versus time in seconds was linear with a slope of 0.056 M-

Bond [772]

Answer:

$C_t=0.165M$

Explanation:

From the question we are told that:

Slope $K=0.056 M-1 s -1$

initial Concentration $C_1=2.2M$

Time $t=100$

Generally the equation for Raw law is mathematically given by

$\frac{1}{C}_t=kt+\frac{1}{C}_0$

$\frac{1}{C}_t=0.056*100+\frac{1}{2.2}_0$

$C_t=0.165M$

4 0

3 years ago

2CuS + 3O2 = 2CuO + 2SO2

Nata [24]

I have no yuuuuu to say anything abt to

4 0

3 years ago

In the following reaction, what is the effect on the direction of the reaction if more SO3 is added to the reaction mixture?

Stolb23 [73]

Answer:

The equilibrium shifts to produce more reactants.

Explanation:

According to the Le- Chatelier principle,

At equilibrium state when stress is applied to the system, the system will behave in such a way to nullify the stress.

The equilibrium can be disturb,

By changing the concentration

By changing the volume

By changing the pressure

By changing the temperature

Consider the following chemical reaction.

Chemical reaction:

2SO₂ + O₂ ⇄ 2SO₃

In this reaction the equilibrium is disturb by increasing the concentration of Product.

When the concentration of product is increased the system will proceed in backward direction in order to regain the equilibrium. Because when product concentration is high it means reaction is not on equilibrium state. As the concentration of SO₃ increased the reaction proceed in backward direction to regain the equilibrium state and more reactant is formed.

3 0

2 years ago

Part 1: What is the final volume in milliliters when 0.730 L of a 44.8 % (m/v) solution is diluted to 23.3 % (m/v)?

Andre45 [30]

part 1 : the final volume : 1.404 L

part 2 : the initial concentration : 4.06 M

<h3>Further explanation </h3>

Dilution is the process of adding a solvent to get a more dilute solution.

The moles(n) before and after dilution are the same.

Can be formulated :

M₁V₁=M₂V₂

M₁ = Molarity of the solution before dilution

V₁ = volume of the solution before dilution

M₂ = Molarity of the solution after dilution

V₂ = Molarity volume of the solution after dilution

part 1 :

M₁=44.8%

V₁=0.73 L

M₂=23.3%

$\tt V_2=\dfrac{M_1.V_1}{M_2}\\\\V_2=\dfrac{44.8\times 0.73}{23.3}\\\\V_2=1.404~L$

part 2 :

V₁=739 ml=0.739 L

V₂=1.5 L

M₂=2

$\tt M_1=\dfrac{M_2.V_2}{V_1}\\\\M_1=\dfrac{2\times 1.5}{0.739}\\\\M_1=4.06$

6 0

2 years ago