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Evgen [1.6K]
2 years ago
15

Carbon monoxide (CO) _____.

Chemistry
2 answers:
cricket20 [7]2 years ago
5 0

Answer:

the last one

Explanation:

All of the other ones are false

postnew [5]2 years ago
4 0

Answer:

is a compound made of oxygen and carbon

Explanation:

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6.3 kJ of energy is required to increase the temperature of some water from 60 °C to 75 °C. The specific heat capacity of water
Andreas93 [3]

Answer:

Mass of the water = 0.1kg is 100g

Explanation:

Mathematically;

Quantity of heat = mass of water * specific heat capacity * temperature change

From the question, we identify the following;

Quantity of heat = 6.3 KJ

1 KJ = 1000 J, so 6.3 KJ = 6.3 * 1000 = 6300 J

Mass of water = ?

Specific heat capacity = 4200

Temperature change is the difference between the final and initial temperature. = 75-60 = 15

6300 = m * 15 * 4200

63 = m * 15 * 42

63 = 630 m

m = 63/630

m = 0.1 kg

4 0
3 years ago
) Given the following balanced equation, determine the rate of reaction with respect to [O2]. If the rate of formation of O2is 7
Travka [436]

Answer:

Rate of the reaction is 0.2593 M/s

-0.5186 M/s is the rate of the loss of ozone.

Explanation:

The rate of the reaction is defined as change in any one of the concentration of reactant or product per unit time.

2O_3\rightleftharpoons 3O_2

Rate of formation of oxygen : 7.78\times 10^{-1} M/s

Rate of the reaction(R) =\frac{-1}{2}\frac{d[O_3]}{dt}=\frac{1}{3}\frac{d[O_2]}{dt}

R=\frac{1}{3}\frac{d[O_2]}{dt}

Rate of formation of oxygen=3 × (R)

7.78\times 10^{-1} M/s=3\times R

Rate of the reaction(R): 0.2593 M/s

Rate of the reaction is 0.2593 M/s

Rate of disappearance of the ozone:

R=-\frac{1}{2}\frac{d[O_3]}{dt}

\frac{d[O_3]}{dt}=-2\times R=-2\times 0.2593\times M/s=-0.5186M/s

-0.5186 M/s is the rate of the loss of ozone.

6 0
3 years ago
Look at the diagram of a fuel cell below.
Ymorist [56]
I’m pretty sure it’s abode and cathode
4 0
3 years ago
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How many grams (m) of glucose are in 165 ml of a 5.50% (m/v) glucose solution? express your answer numerically in grams?
Leya [2.2K]
     <span> mass of glucose = 0.055 *165 = 9.075 g

vol of methyl alc = 0.185 * 1.87 = 0.346 L = 346 ml

% NaCl ( m/v ) = mass NaCl * 100/ vol of soln

or Vol of Soln = mass NaCl / % NaCl (m/v)

= 32.1 * 100 / 6 = 535 ml the total vol of soln</span>
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3 years ago
What is the answer to “An element is:”
Jobisdone [24]
A. A pure chemical substance consisting of one type of atom
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2 years ago
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