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3 years ago

What is the change in momentum of a 40 kg runner that travels from 5 m/s to 11 m/s

1 answer:

8 0

p=mv where p is momentum in kgms-1, m is mass/kg and v is velocity/ms-1

Therefore to find the change in momentum we can just substitute the numbers in and find the difference.

At 5ms-1 the runner has a momentum of 5*40=200kgm/s
At 11ms-1 the runner has a momentum of 11*40=440kgm/s

Finding the difference, the change of momentum is 240kgm/s

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Electrons are accelerated in the picture tube of a television through potential difference of 8.00 * 10 ^ 3 V. (Use the values q

maria [59]

Answer:

$\lambda=1.37\times 10^{-11}\ m$

Explanation:

Give that,

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3 years ago

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Explanation:

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3 years ago

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3 years ago

Read 2 more answers

) A stone initially moving at 8.0 m/s on a level surface comes to rest due to friction after it travels 11 m. What is the coeffi

natali 33 [55]

Answer:

-0.3

Explanation:

F' = μmg ........... Equation 1

Where F' = Frictional force, μ = coefficient of kinetic friction, m = mass of the stone, g = acceleration due to gravity.

But,

F' = ma ............ Equation 2

Where a = acceleration of the stone.

Substitute equation 2 into equation 1

ma = μmg

dividing both side of the equation by m

a = μg

make μ the subject of the equation

μ = a/g............... Equation 3

From the equation of motion,

v² = u²+2as................. Equation 4

Where v and u are the final and the initial velocity respectively, s = distance.

Given: v = 0 m/s (to rest), u = 8.0 m/s, s = 11 m.

Substitute into equation 4

0² = 8² + 2×11×a

22a = -64

a = -64/22

a = -32/11 m/s² = -2.91 m/s²

substitute the values of a and g into equation 3

μ = -2.91/9.8

μ = -0.297

μ ≈ -0.3

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3 years ago

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vagabundo [1.1K]

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