Answer:
C2H6O(aq) + 3O2(g) → 2CO2(g) + 3H2O(l)
Explanation:
Step 1: data given
The reactants are:
ethanol = C2H6O(aq)
oxygen gas = O2(g)
The products are:
gaseous carbon dioxide = CO2(g)
liquid water = H2O(l)
Step 2: The unbalanced equation
C2H6O(aq) + O2(g) → CO2(g) + H2O(l)
Step 3: Balancing the equation
C2H6O(aq) + O2(g) → CO2(g) + H2O(l)
On the left side we have 2 time C (in C2H6O), on the right side we have 1x C (in CO2). To balance the amount of C on both sides, we have to multiply CO2 on the right side by 2.
C2H6O(aq) + O2(g) → 2CO2(g) + H2O(l)
On the left side we have 6x H (in C2H6O), on the right side we have 2x H(in H2O). To balance the amount of H on both sides, we have to multiply H2O on the right side by 3.
C2H6O(aq) + O2(g) → 2CO2(g) + 3H2O(l)
On the right side we have 7x O (4x O in 2CO2 and 3x O in 3H2O), on the left side we have 3x O (1x in C2H6O and 2x in O2). To balance the amount of O on both sides, we have to multiply O2 on the left side by 3. Now the equation is balanced.
C2H6O(aq) + 3O2(g) → 2CO2(g) + 3H2O(l)
Answer:
option a, During allotropic transformation, the number of atoms in the material changes.
Explanation:
Allotrops are different crystalline forms of the same element. So, two allotrops of an element have same number of atoms.
for example diamond, graphite, graphene, fullerene are allotropic forms of carbon.
Allpotops differ in physical and chemical properties. So, volume changes during alloptropic transformation. So, statement b is correct.
Allotropic transformation is the transformation of one allotropic form to other therefore, number of atom does not change during allotropic transformation.
Chemical species having same atomic number or same no. of protons are called isotopes. so statement c is correct.
When an electron is added to the neutral element, electronic repulsion increases which lead to the increase in atomic size, So, statement d is also correct.
So among given, option a is incorrect
<span>C. the view that the atom cannot be broken down further than protons</span>
Answer:
[KBr] = 454.5 m
Explanation:
m is a sort of concentration that indicates the moles of solute which are contianed in 1kg of solvent.
In this case, the moles of solute are 0.25 moles.
Let's determine the mass of solvent in kg.
Density of heavy water, solvent, is 1.1 g/L and our volume is 0.5L.
1.1 g = mass of solvent / 0.5L, according to density.
mass of solvent = 0.5L . 1.1g/L = 0.55 g
We convert the mass to kg → 0.55 g . 1kg /1000g = 5.5×10⁻⁴ kg
m = mol/kg → 0.25 mol /5.5×10⁻⁴ kg = 454.5 m
