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alexira [117]
3 years ago
8

How many moles are in 25 grams of Li? How do you know?

Chemistry
1 answer:
Ipatiy [6.2K]3 years ago
8 0

Answer:

3.6mol Li

Explanation:

To get the amount of moles from the mass we divide the mass by the molar mass.

25g ÷ 6.941g/mol = 3.6mol Li

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3 years ago
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How many moles are in 272 grams of hydrogen peroxide (H2O2) ?
Strike441 [17]

Answer:

8 moles

Explanation:

When we are asked to convert from grams of a substance into moles, we have to use the substance's molar mass.

Meaning that for this problem, we'll <em>use the molar mass of hydrogen peroxide</em> (H₂O₂), as follows:

  • 272 g ÷ 34 g/mol = 8 mol

There are 8 moles in 272 grams of hydrogen peroxide.

7 0
3 years ago
PLEASE ANSWER ASAP AND SHOW WORK: A camping stove uses a 5.0 L propane tank that holds 68.0 moles of liquid C3H8. How large a co
seropon [69]

<u>Answer:</u> The volume of the container needed is 554.6 L

<u>Explanation:</u>

To calculate the volume of the gas, we use the equation given by ideal gas which follows:

PV=nRT

where,

P = pressure of the gas = 3.0 atm

V = Volume of the gas = ? L

T = Temperature of the gas = 25^oC=[25+273]K=298K

R = Gas constant = 0.0821\text{ L.atm }mol^{-1}K^{-1}

n = number of moles of propane gas = 68.0 moles

Putting values in above equation, we get:

3.0atm\times ?L=68mol\times 0.0821\text{ L.atm }mol^{-1}K^{-1}\times 298K\\\\V=\frac{68\times 0.0821\times 298}{3.0}=554.6L

Hence, the volume of the container needed is 554.6 L

6 0
3 years ago
The Lineweaver–Burk plot, which illustrates the reciprocal of the reaction rate ( 1 / v ) versus the reciprocal of the substrate
lesya [120]

Answer:

  • x-intercept = \frac{-1}{Km}
  • y-intercept = \frac{1}{Vmax}
  • Slope = \frac{Km}{Vm}

Explanation:

Please check the graph attached.

7 0
3 years ago
Which is not the same as 5.63 <br> grams
Anarel [89]
We must first convert the weight in grams to milligrams and hectograms to find the right answer. 5.63 grams 0.0563 hectograms
5.63 grams=5,630 milligrams
So it's 5,630
3 0
4 years ago
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