All categories

3 years ago

In the following redox reaction which is the oxidizing agent and which is the reducing agent? AlCl3 + Na NaCl + Al

Chemistry

1 answer:

horrorfan [7]3 years ago

4 0

Answer : Al

Explanation :

- For a given redox reaction there must be an oxidizing agent/(s) and a reducing agent/(s).

- the oxidizing agent is the substance that undergoes reduction process (gaining electrons or loss of oxygen atoms), meanwhile, the reducing agent is the substance that undergoes oxidation process (loss of electrons or gaining of oxygen atoms).

- In the reaction above, the oxidation number of (Al) in AlCl3 is (3+). However, the oxidation number of (Al) in the products is zero because it exists as a single element.

Therefore, changing from (3+) to zero means gaining of (3) electrons to neutralize the previously existing (3) protons on (Al) in AlCl3.

So Al is the oxidizing agent..

You might be interested in

A student combined two colorless aqueous solutions. One of the solutions contained Na2CO3 as the solute and the other contained

Kazeer [188]

Answer:

Bubbles will be formed when two solutions will be combined.

Explanation:

When the solution containing $Na_{2}CO_{3}$ and $HCl$ as a solute will be combined, the reaction will be as follows,

$Na_{2}CO_{3}(aq) + 2HCl(aq) \rightarrow 2NaCl(aq)+ H_{2}O(l)+CO_{2}(g)$

As a result of combination of the two solutions bubbles will be formed which will depict the evolution of carbon dioxide gas.

5 0

3 years ago

What is the final temperature when 150.0 g of water at 90.0 °c is added to 100.0 g of water at 30.0 OC? Note that C, of water ca

levacccp [35]

Answer : The final temperature is, $337.8K$

Explanation :

$Q_{absorbed}=Q_{released}$

As we know that,

$Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})$

$m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]$ .................(1)

where,

q = heat absorbed or released

$m_1$ = mass of water at $90^oC$ = 150 g

$m_2$ = mass of water at $30^oC$ = 100 g

$T_{final}$ = final temperature = ?

$T_1$ = temperature of lead = $90^oC=273+90=363K$

$T_2$ = temperature of water = $30^oC=273+30=303K$

$c_1\text{ and }c_2$ = same (for water)

Now put all the given values in equation (1), we get

$150\times (T_{final}-363)=-[100\times (T_{final}-303)]$

$T_{final}=337.8K$

Therefore, the final temperature is, $337.8K$

8 0

4 years ago

Read 2 more answers

What is the mass of 4.5 x 10^22 molecules of hydrogen peroxide (H2O2)? Show your work in the space below.

valentinak56 [21]

Given :

Number of molecules of hydrogen peroxide, N = 4.5 × 10²².

To Find :

The mass of given molecules of hydrogen peroxide.

Solution :

We know, 1 mole of every compound contains Nₐ = 6.022 × 10²³ molecules.

So, number of moles of hydrogen peroxide is :

$n = \dfrac{N}{N_a}\\\\n = \dfrac{4.5\times 10^{22}}{6.022\times 10^{23}}\\\\n = 0.0747 \ moles$

Now, mass of hydrogen peroxide is given as :

m = n × M.M

m = 0.0747 × 34 grams

m = 2.54 grams

Hence, this is the required solution.

6 0

3 years ago

What usually happens to the outer electrons of metallic atoms when they combine chemically with nonmetallic atoms?

aleksandr82 [10.1K]

They will mostly fill the octet rule rather than the nonmetal counterparts. Especially in the case of hydrogen

7 0

3 years ago

Look at the picture above. what method is used to separate the different parts of crude oil?

baherus [9]

Answer:

A very special way of separation called FRACTIONAL DISTILLATION will be used to separate various components from Crude oil.

Fractional distillation is the separation of a mixture into its component parts, or fractions. Chemical compounds are separated by heating them to a temperature at which one or more fractions of the mixture will vaporize. It uses distillation to fractionate.

4 0

3 years ago