Z=1 is the formula i would have to see the following lol
P = nRT/V
P = 3.5 x 10^-3 x 0.082 x 298 /0.5
P = 0.171 m Hg
P = 171 mm Hg
hope this helps
We need to dilute 0.400 mol of copper (II) sulfate, how do we know, how many weigh of

we have to dilute??
It's simple.

Using a periodic table we can find the molar mass of


Then

now we can replace it


Then we have to dilute 63.84 grams of copper (II) sulfate in 1 L of water to obtain a solution with 0.400M
Density = mass/volume
So..
D = 10.74/5
D = 2.148 g/mL ^3