Answer:
1.2 × 10⁴ cal
Explanation:
Given data
- Mass of water (m): 300 g
- Initial temperature: 80 °C
- Final temperature: 40°C
We can calculate the heat released by the water () when it cools using the following expression.
where
c is the specific heat capacity of water (1 cal/g.°C)
According to the law of conservation of energy, the sum of the heat released by the water () and the heat absorbed by the reaction (
) is zero.
