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coldgirl [10]
3 years ago
14

Please help urgent Balance the following word equation:

Chemistry
1 answer:
LekaFEV [45]3 years ago
8 0

Answer:

AlCl3 + 3Na > Al + 3NaCl

Explanation:

AlCl3+Na → Al + NaCl

Al =1 Al=1

Cl =3 Cl = 1

Na=1. Na = 1

so balance

and it would be

Alcl3 + 3Na → Al + 3NaCl

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How many molecules of ammonia are formed in the following equation: N2+3H2→2NH3
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Answer:

  • <u>two molecules of ammonia are formed by the reaction of one nitrogen and three hydrogen molecules.</u>

Explanation:

The  balanced chemical equation provides information on:

  • <u>Reactants</u>: those are the compounds that appear of the left side of the equation, each with its chemical formula.

  • <u>Products</u>: those are the compounds that appear on the right side of the equation, again, each with its chemical formula.

  • <u>Ratio</u>: the coefficients of each compound (the number to the left of the chemical formula) represent the ratio of the number of molecules that react and are formed.

In the given equation you have:

  • Equation: N₂ + 3H₂ → 2NH₃

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This reaction was at equilibrium when 0.2 atm of iodine gas was pumped into the container, what happened to the equilibrium and
n200080 [17]

Answer:

Q was < K. Partial pressure of hydrogen decreased, iodine increased

Explanation:

<em>After iodine was added the Q was [Select] K so the reaction shifted toward the Products [Select] ,The partial pressure of hydrogen [Select], Iodine [Select] |,and hydrogen iodide Decreased</em>

Based on the equilibrium:

H2(g) + I2(g) ⇄ 2HI(g)

K of equilibrium is:

K = [HI]² / [H2] [I2]

<em>Where [] are concentrations at equilibrium</em>

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Q = [HI]² / [H2] [I2]

<em>Where [] are actual concentrations of the reactants.</em>

<em />

When the reaction is in equilibrium, K=Q.

But as [I2] is increased, Q decreases and Q was < K

The only concentration that increases is [I2], doing partial pressure of hydrogen decreased, iodine increased

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