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3 years ago

Fill up the blank :- If you are using the unit Kelvin, you are measuring the average ......

Chemistry

2 answers:

patriot [66]3 years ago

6 0

Kelvin is a unit for measuring temperature on the absolute scale. Therefore, temperature should be the answer

EastWind [94]3 years ago

5 0

<span>If you are using the unit Kelvin, you are measuring the average </span>kinetic energy per particle. Kelvin is one of the 7 base units in the ISU and is symbolized with a K.

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What is the molar mass of 81.50 g of gas

garik1379 [7]

The molar mass of gas = 238.29 g/mol

<h3>Further explanation</h3>

Given

mass = 81.5 g

P=1.75 atm

V=4.92 L

T=307 K

Required

molar mass

Solution

The gas equation can be written

$\large{\boxed{\bold{PV=nRT}}$

$\tt n=\dfrac{mass}{molar~mass}$

So the equation becomes :

$\tt Molar~mass=\dfrac{mRT}{PV}$

Input the value :

$\tt M=\dfrac{81.5\times 0.082\times 307}{1.75\times 4.92}\\\\M=238.29~g/mol$

5 0

3 years ago

Read 2 more answers

Warm air holds _____.<br>

Agata [3.3K]

Answer:

less water than cl air

Explanation:

i think

8 0

3 years ago

An empty vial weighs 55.32 g. (a) If the vial weighs 185.56 g when filled with liquid mercury (d = 13.53 g/cm3). What i its volu

Tasya [4]

Answer:

a) Volume of vial= 9.626cm3

b) Mass of vial with water = 62.92 g

Explanation:

a) Mass of empty vial = 55.32 g

Mass of Vial + Hg = 185.56 g

Therefore,

$mass\ of\ Hg = 185.56-55.32 = 130.24 g$

Density of Hg = 13.53 g/cm3

$Volume\ of\ vial = Volume\ of\ Hg = \frac{Mass}{Density} \\\\= \frac{130.24g}{13.53g/cm3} = 9.626 cm3$

b) Volume of water = volume of vial = 9.626 cm3

Density of water = 0.997 g/cm3

$Mass\ of\ water = Density*volume = 0.997g/cm3*9.626cm3=9.60 g\\\\Total\ Mass\ of\ vial = Empty\ vial + mass\ of\ water\\= 53.32+9.60= 62.92g$

3 0

3 years ago

Can anyone explain enzymes in a simple way?

Sedaia [141]

Enzymes are biological catalysts which means they accelerate chemical reactions.
Hope this helps :)

4 0

3 years ago

Select the fastest way to differentiate between the organic and aqueous layers of an extraction.a. Hold a white piece of paper b

valentinak56 [21]

Answer:

b. Add a few drops of one of the layers to a test tube containing 1 mL of water. Shake the test tube to determine the solubility of the layer in water

Explanation:

Option a is not true, it depends on the compound being extracted.

Option c is not true, although most of the solvents used in extractions have lower boiling point than water there are exceptions, for example toluene.

Option d is not true. Again most of the solvents used in extractions are less dense than water, there are many exceptions, for example chloroform, so for equal volumes the chloroform layer will weigh more.

Option b. is the correct one.

One will test the miscibility of the layer in water. If it inmiscible then one would know is the organic layer. If it is the aqueous layer then it will completely be miscible.

6 0

3 years ago