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Lesechka [4]
3 years ago
15

Can someone please help with question 6

Mathematics
1 answer:
xeze [42]3 years ago
7 0

Area of triangle

= (1/2) x base x height

= (1/2) x 15 x 32

= 240 ft^2 (Sorry, I use the metrical system so I don't know what's the unit)

Let the point where the line in the middle of the triangle touches the bottom end of the triangle be A

From A to the right vertice (or corner) of the triangle, the length is, using pythagoras theorem,

= √((43)^2 - (32)^2)

= √825

Length of other side of triangle, using pythagoras theorem

= √((32)^2 + (15 - √825)^2)

(Sorry I don't have a calculator now so I can't calculate this out, so we'll call this X)

Therefore, perimeter

= 15 + 43 + (that whole chunk up there called X)

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Nora measured the angles of a triangle. Two of the angles measured 20° What was the measure of the third angle of Nora’s triangl
aivan3 [116]

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Step-by-step explanation:

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8 0
3 years ago
Shureka Washburn has scores of 67​, 68​, 76​, and 63 on her algebra tests. a. Use an inequality to find the scores she must make
mash [69]
Average=(total number)/(number of items)
given that the final exam counts as two test, let the final exam be x. The weight of the final exams on the average is 2, thus the final exam can be written as 2x because any score Shureka gets will be doubled before the averaging.
Hence our inequality will be as follows:
(67+68+76+63+2x)/6≥71
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274+2x≥71×6
274+2x≥426
2x≥426-274
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b] The above answer is x≥76, the mean of this is that if Shureka is aiming at getting an average of 71 or above, then she should be able to get a minimum score of 76 or above. Anything less than 76 will drop her average lower than 71.


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Answer:

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6 0
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