1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Dafna1 [17]
3 years ago
9

A compound has an M-/M-2 ratio of 75:25. Which of the following could be the molecular formula of this compound? a) CH2Br2 b) CH

2Cl2 c) CHCI d) CH:Bre) CHF
Chemistry
1 answer:
Lera25 [3.4K]3 years ago
3 0

Answer:

c) CH₃Cl

Explanation:

Due the relative abundance of chlorine and bromine. It is possible to determine which of the halogens is present in a mass spectrum of a organic compound:

The Cl-35, Cl-37 have a relative abundance of 75/25; Br-79 and Br-81 of 50/50.

For that reason, if a compound has a M/M+2 ratio of 75:25 you can be sure the compound has 1 Cl in its structure. Thus, the only possible structure is:

<h3>c) CH₃Cl</h3>
You might be interested in
2h3po4 + 3mg(oh)2 → mg3(po4)2 + 6h2o phosphoric acid, h3po4, is neutralized by magnesium hydroxide, mg(oh)2, according to the eq
Rina8888 [55]
The balanced equation for the neutralisation reaction is as follows
2H₃PO₄ + 3Mg(OH)₂ --> Mg₃(PO₄)₂ + 6H₂O
stoichiometry of H₃PO₄ to H₂O is 2:6
number of H₃PO₄ moles reacted - 0.24 mol
if 2 mol of H₃PO₄ form 6 mol of H₂O
then 0.24 mol of H₃PO₄ forms - 6/2 x 0.24 = 0.72 mol of H₂O
therefore 0.72 mol of H₂O are formed 
4 0
3 years ago
Enter the correct ground-state (or lowest energy) configuration based on the number of electrons: 1s^4 2s^4 2p^12.
Blababa [14]

Answer:

The ground state configuration is the lowest energy, most stable arrangement. An excited state configuration is a higher energy arrangement (it requires energy input to create an excited state). Valence electrons are the electrons utilised for bonding.

or the

FIGURE 5.9 The arrow shows a second way of remembering the order in which sublevels fill. Table 5.2 shows the electron configurations of the elements with atomic numbers 1 through 18.

Element Atomic number Electron configuration

sulfur 16 1s22s22p63s23p4

chlorine 17 1s22s22p63s23p5

argon 18 1s22s22p63s23p6

or the

Two electrons

Two electrons fill the 1s orbital, and the third electron then fills the 2s orbital. Its electron configuration is 1s22s1.

Explanation:

<em>Choose </em><em>your </em><em>answer </em>

<em>brainlilest </em><em>me</em>

<em><u>CARRY </u></em><em><u>ON </u></em><em><u>LEARNING</u></em>

6 0
3 years ago
3. The breaking down of rocks into smaller pieces by physical
shutvik [7]

Answer:

A. Chemical weathering

3 0
3 years ago
Can someone help please !!!!
Naya [18.7K]

Answer:

x = 231/90 Th

Explanation:

3 0
3 years ago
PLZ HELP ME!!! I'll give brainliest to whoever answers this along with 15 points!
Readme [11.4K]

I would say diamond, because it consists only of carbon

3 0
2 years ago
Other questions:
  • What is the number of carbon atoms in the ring portion of the haworth structure of glucose?
    15·1 answer
  • A sample of gas contains 6.25 × 10-3 mol in a 500.0 mL flask at 265°C. What is the pressure of the gas in kilopascals? Which var
    13·2 answers
  • I don't know how to do this, pls help!
    8·2 answers
  • Enter your answer in the provided box. Consider the reaction: N2(g) + 3H2(g) → 2NH3(g) Suppose that a particular moment during t
    8·1 answer
  • What is the molarity of a solution prepared by dissolving 10.0g of kno3 in 250 ml of solution
    10·1 answer
  • The circular flow model interacts between which sectors of the economy? Select THREE answers.
    14·1 answer
  • What is metal ? Where does it coke from ?
    6·2 answers
  • Which of the following is the atomic number of an alkali metal?​
    11·1 answer
  • Many reactions involve a change in hybridization of one or more atoms in the starting material. In this reaction, determine the
    10·1 answer
  • What is the mass of one mole of NaCl?
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!