<span>3NO2 + H2O = 2HNO3 + NO
moles of nitric oxide:
under STP (Standard Tempreture and Pressure)
22.4L of any gas = 1mole
</span><span>so 30L of NO: 30 / 22.4 = 1.33928571429 moles
</span><span>
so you use the ratios 3:1 to find the moles of the nitrogen dioxide: </span>1.33928571429 x 3 (is the ratio) =<span>4.01785714286mol</span>⁻¹ of NO₂<span>
</span><span>
now to find liters use: L = Moles x 22.4
L of NO</span>₂ <span>= 90L
hope that helps
</span>
Use the equation for uniform acceleration:
distance = Vo*t + a * t^2 / 2
As the car is initially at rest, Vo = 0
=> distance = a * t^2 / 2.
Now solve for a and replace the data of time and distance:
a = 2 * distance / (t^2)
a = 2 * 120m / (6.32s)^2 = 240m / 39.9424 s^2 = 6.009 m/s^2
Which approximates to 6 m/s^2.
So, the answer is the option B.) 6 meters / second^2
Explanation:
here's the answer to your question
