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3 years ago

Compared with halogens, the alkali metals in the same period has

Chemistry

1 answer:

Rufina [12.5K]3 years ago

3 0

Alkali metals have the lowest electronegativities, while halogens have the highest.

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⦁ How many moles of carbon dioxide will be produced by the complete reaction of 2.0 mol of glucose (C6H12O6), according to the f

SashulF [63]

Answer:

i think 12 moles of CO2 will be produced

3 0

2 years ago

What volume (in mililiters) of oxygen gas is required to react with 4.03 g of my at stp

goldenfox [79]

You must use 1880 mL of O₂ to react with 4.03 g Mg.

A_r: 24.305

2Mg + O₂ ⟶ 2MgO

<em>Moles of Mg</em> = 4.03 g Mg × (1 mol Mg/24.305 g Mg) = 0.1658 mol Mg

<em>Moles of O₂</em> = 0.1658 mol Mg × (1 mol O₂/2 mol Mg) = 0.082 90 mol O₂

STP is 25 °C and 1 bar. At STP, 1 mol of an ideal gas has a volume of <em>22.71 L</em>.

<em>Volume of O₂</em> = 0.082 90 mol O₂ × (22.71 L O₂/1 mol O₂) = 1.88 L = 1880 mL

4 0

2 years ago

You place 12.0 milliliters of water in a graduated cylinder. Then you add 15.0 grams of metal to the water and the new water lev

Marrrta [24]

Answer:

<h3>The answer is 7.85 g/mL</h3>

Explanation:

The density of a substance can be found by using the formula

$density = \frac{mass}{volume} \\$

volume = final volume of water - initial volume of water

volume = 13.91 - 12 = 1.91 mL

We have

$density = \frac{15}{1.91} \\ = 7.853403141...$

We have the final answer as

Hope this helps you

8 0

3 years ago

Read 2 more answers

It’s about the periodic table of elements

Pie

Yes what the other person said can I plz get an thanks

3 0

2 years ago

Hydrogen gas is filled in a 224 ml glass container at 0 degree celcius and 1 atmospheric pressure. What are the number of molecu

Step2247 [10]

Answer:

$\boxed{\text{6.02 $\math{\times 10^{21}}$ molecules}}$

Explanation:

A pressure of 1 atm and a temperature of 0 °C is the old definition of STP. Under these conditions, 1 mol of a gas occupies 22.4 L.

1. Calculate the moles of hydrogen.

$n = \text{0.224 L} \times \dfrac{\text{1 mol}}{\text{22.4 L}} = \text{0.0100 mol}$

2. Calculate the number of molecules

$\text{No. of molecules} = \text{0.0100 mol} \times \dfrac{\text{6.022 $\times 10^{23}$ molecules}}{\text{1 mol}}\\\\= \textbf{6.02 $\mathbf{\times 10^{21}}$ molecules}\\\\\text{The sample contains }\boxed{\textbf{6.02 $\mathbf{\times 10^{21}}$ molecules}}$

8 0

3 years ago

Read 2 more answers