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SOVA2 [1]
3 years ago
12

Describe in detail how you would determine the density of a potato that is too large to fit into a graduated cylinder. (Hint: Th

is question wants you to find a different way to measure density than using the volume of the entire potato.)
Chemistry
1 answer:
Mnenie [13.5K]3 years ago
7 0

Answer:

The density of a potato is \dfrac{M}{V'}

Explanation:

Given that,

A potato that is too large to fit into a graduated cylinder.

Let us consider the mass of potato is M and volume of entire potato is V'.

The volume of water is V.

We know that,

Density :

The density is equal to the mass divided by volume.

In mathematically,

\rho=\dfrac{m}{V}

Where, m = mass

V = volume

We need to calculate the volume of potato

Using formula for volume

V'=V''-V

Where, V' = volume of potato

V''=Volume of combine water and potato

V = volume of water

We need to determine the density of a potato

Using  formula of density

Density\ of\ potato=\dfrac{Mass\ of\ potato}{volume\ of\ entire\ potato}

Put the value into the formula

\rho=\dfrac{M}{V'}

Hence, The density of a potato is \dfrac{M}{V'}

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The first ionization energy, e, of a potassium atom is 0.696 aj. what is the wavelength of light, in nm, that is just sufficient
elena55 [62]
The formula to be used for this problem is as follows:

E = hc/λ, where h is the Planck's constant, c is the speed of light and λ is the wavelength. Also 1 aJ = 10⁻¹⁸ J

0.696×10⁻¹⁸ = (6.62607004×10⁻³⁴ m²·kg/s)(3×10⁸ m/s)/λ
Solving for λ,
λ = 2.656×10⁻⁷ m or <em>0.022656 nm</em>
6 0
3 years ago
How many grams hydrogen in 4.5 mol H2SO4
swat32
H2SO4 ---> 2H^+ + SO4^2-

Hence n H+ = 9 mols

Mass of H = nM = (9*1) = 9g


Alternately

mass of H2SO4= nM= 4.5*98= 441

Mass of H= mass h2so4 * molar mass of H/molar mass of h2so4
Mass of H= 441 * 2/98 = 9g

4 0
3 years ago
Why ammonium is not a molecular ion
In-s [12.5K]

Answer:

See below

Explanation:

Ammonium (NH_{4}^+) is not a molecular ion because it is just a poly-atomic ion. A molecular ion has a "negative or positive charge" as a whole but the positive charge on here is not on the whole. So, it is a poly-atomic ion and not molecular ion.

3 0
3 years ago
How does heat move from one place to another on the troposphere
d1i1m1o1n [39]

I thinlk it's by radiation?......

8 0
4 years ago
Determine the freezing point and boiling point of a solution that has 68.4 g of sucrose
Ymorist [56]

Answer:

Freezing T° of solution = - 3.72°C

Boiling T° of solution =  101.02°C

Explanation:

To solve this we apply colligative properties. Firstly, freezing point depression:

ΔT = Kf . m . i

ΔT = Freezing T° of pure solvent - Freezing T° of solution

Kf = Cryoscopic constant, for water is 1.86 °C/m

m = molality (moles of solute in 1kg of solvent)

i = Ions dissolved in solution

Our solute is sucrose, an organic compound so no ions are defined. i = 1.

Let's determine the moles: 68.4 g . 1mol/ 342g = 0.2 moles

molality = 0.2 mol / 0.1kg of water = 2 m

We replace data: ΔT = 1.86°C/m . 2m . 1

Freezing T° of solution = - 3.72°C

Now, we apply elevation of boiling point: ΔT = Kb . m . i

ΔT = Boiling T° of solution - Boiling T° of  pure solvent

Kf = Ebulloscopic constant, for water is 0.512 °C/m

We replace:

Boiling T° of solution - Boiling T° of pure solvent = 0.512 °C/m . 2 . 1

Boiling T° of solution = 0.512 °C/m . 2 . 1 + 100°C → 101.02°C

6 0
3 years ago
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