If an atom loses or gains an electron, it becomes a charged particle or ...
2 answers:
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Answer:
Explanation:
If the block remains in equilibrium on the inclined plane
then we can say that component of weight along the inclined plane is counter balanced by the static friction force.
Here we know that maximum static friction force on the block is given by
here we have
now the component of weight along the inclined is balance by maximum static friction force
Answer:
The magnitude of the force the light beam exerts on the man is 5.9 x 10⁻⁵N
(b) the force the light beam exerts is much too small to be felt by the man.
Explanation:
Given;
cross-sectional area of the man, A = 0.500m²
intensity of light, I = 35.5kW/m²
If all the incident light were absorbed, the pressure of the incident light on the man can be calculated as follows;
P = I/c
where;
P is the pressure of the incident light
I is the intensity of the incident light
c is the speed of light
F = PA
where;
F is the force of the incident light on the man
P is the pressure of the incident light on the man
A is the cross-sectional area of the man
F = 1.18 x 10⁻⁴ x 0.5 = 5.9 x 10⁻⁵ N
The magnitude of the force the light beam exerts on the man is 5.9 x 10⁻⁵ N
Therefore, the force the light beam exerts is much too small to be felt by the man.
Answer:
The correct answer is "3899.92 N".
Explanation:
The given values are:
Force,
Ratio,
As we know,
Area,
or,
⇒
On substituting the value of "A", we get
⇒
⇒
On applying cross-multiplication, we get
⇒
On substituting the given values, we get
⇒
⇒
⇒