1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
postnew [5]
2 years ago
5

When selling on the street, dealers may not know the purity of the ketamine they have, and thus users do not know exactly how mu

ch ketamine they are receiving. It is unlikely that the ketamine is pure, or even that different batches of ketamine have the same purity. Assume the drug the user typically buys is only 25% ketamine, and therefore, the user actually dissolved 0.250 g ketamine in 1/4 cup of water to make the solution instead of 1 g in the previous question. 1 cup = 236.5 mL What volume of this ketamine solution would the 65.0 kg user have to inject to experience a high at 0.400 mg/kg? volume: mL What volume of this ketamine solution would the user have to inject to become unconscious at 2.00 mg/kg? of use contact us help What volume of this ketamine solution would the user have to inject to become unconscious at 2.00 mg/kg?
Chemistry
1 answer:
fiasKO [112]2 years ago
5 0

Answer:

a. 6.15 mL b. 30.73 mL

Explanation:

a. What volume of this ketamine solution would the 65.0 kg user have to inject to experience a high at 0.400 mg/kg?

Since we have 0.250 g of ketamine in 1/4 cup of water and 1 cup of water equals 236.5 mL, we need to find the concentration of ketamine we have.

So concentration of ketamine C = mass of ketamine, m/volume of water, V

m = 0.250 g and V = 1/4 cup = 1/4 × 236.5 mL = 59.125 mL

So, C = m/V = 0.250 g/59.125 mL = 0.00423 g/mL = 4.23 mg/mL

Since the user has a mass of 65 kg and requires a high at 0.400 mg/kg, the mass of ketamine for this high is M = 65 kg × 0.400 mg/kg = 26 mg

Since mass, M = concentration ,C × volume, V

M = CV

V = M/C

The volume of ketamine required for the 0.400 mg/kg high is

V = 26 mg/4.23 mg/mL

V = 6.15 mL

b. What volume of this ketamine solution would the user have to inject to become unconscious at 2.00 mg/kg?

Since the concentration of ketamine is C = 4.23 mg/mL, and Since the user has a mass of 65 kg and requires an injection of 2.00 mg/kg to be unconscious, the mass of ketamine required to be unconscious is M' = 65 kg × 2.00 mg/kg = 130 mg

Since mass, M' = concentration ,C × volume, V

M' = CV

V = M/C

The volume of ketamine required for the 2.00 mg/kg unconscious injection is

V = 130 mg/4.23 mg/mL

V = 30.73 mL

You might be interested in
Which of the following possible outcomes regarding the universe do scientists think is most likey?
hichkok12 [17]
The universe will continue to expand
5 0
3 years ago
Read 2 more answers
Twenty students were surveyed to find out how many hours of TV they watch during a school week. The results are shown to the rig
natulia [17]

Answer: 4.5

Explanation:

Just did it

8 0
2 years ago
Read 2 more answers
What is the solubility product expression for Ag2CO3
Dominik [7]
<span> Ksp = [Ag+]^2[CO32-]that should be it </span>
7 0
3 years ago
In the absence of sodium methoxide, the same alkyl bromide gives a different product. Draw an arrowpushing mechanism to account
hoa [83]

Answer:

See explanation below

Explanation:

The question is incomplete, cause you are not providing the structure. However, I found the question and it's attached in picture 1.

Now, according to this reaction and the product given, we can see that we have sustitution reaction. In the absence of sodium methoxide, the reaction it's no longer in basic medium, so the sustitution reaction that it's promoted here it's not an Sn2 reaction as part a), but instead a Sn1 reaction, and in this we can have the presence of carbocation. What happen here then?, well, the bromine leaves the molecule leaving a secondary carbocation there, but the neighbour carbon (The one in the cycle) has a more stable carbocation, so one atom of hydrogen from that carbon migrates to the carbon with the carbocation to stabilize that carbon, and the result is a tertiary carbocation. When this happens, the methanol can easily go there and form the product.

For question 6a, as it was stated before, the mechanism in that reaction is a Sn2, however, we can have conditions for an E2 reaction and form an alkene. This can be done, cause the extoxide can substract the atoms of hydrogens from either the carbon of the cycle or the terminal methyl of the molecule and will form two different products of elimination. The product formed in greater quantities will be the one where the negative charge is more stable, in this case, in the primary carbon of the methyl it's more stable there, so product 1 will be formed more (See picture 2)

For question 6b, same principle of 6a, when the hydrogen migrates to the 2nd carbocation to form a tertiary carbocation the methanol will promove an E1 reaction with the vecinal carbons and form two eliminations products. See picture 2 for mechanism of reaction.

3 0
3 years ago
if a leaf falls from a tree we assume that it is in free fall and not affected by air resistance, how many force vectors does th
lakkis [162]
Just the force of gravity down. 
7 0
3 years ago
Other questions:
  • Suppose 7 pints of a 23​% alcohol solution is mixed with 3 pints of a 70​% alcohol solution. what is the concentration of alcoho
    12·1 answer
  • How is heat energy transferred if it has direct contact between a warm object and a cold object?
    13·1 answer
  • Pleas help fill in blank
    13·1 answer
  • How many mol are in 8.23 x 10^24 formula units of calcium carbonate
    10·1 answer
  • The equation for the pH of a substance is pH = –log[H+], where H+ is the concentration of hydrogen ions. A basic solution has a
    14·2 answers
  • What is the atmosphere
    12·2 answers
  • What is the maximum number of electrons in an atom that can have the following quantum numbers?Part An=2 Ms= -1/2______________e
    13·1 answer
  • A particular reactant decomposes with a half-life of 121 s when its initial concentration is 0.357 M. The same reactant decompos
    15·1 answer
  • Q+ ( poistive ion ) is an ion of element Q.<br> What has the highest value in the ion?
    9·2 answers
  • Why does water dissolve ionic compounds and solar compounds?
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!