The teacher prepares 2.50 liters (l) of a salt solution for a class experiment, in this quantity 2.65 quartz are present.
<h3>What is conversion factor?</h3>
Conversion factor is a quantity which will be multiplied or divide with any other measurement for the conversion of that measurement.
Given that quantity of salt solution = 2.50 L
We know that, 1 L = 1.06 qt
Here conversion factor is 1.06 qt/L as it will be multiplied on given measurement to convert into quartz as:
2.50L = 2.50L × 1.06qt/L = 2.65qt
Hence required value is 2.65qt.
To know more about conversion factor, visit the below link:
brainly.com/question/97386
Convert everything to one base unit (let's do ft/s in this case)
There are 660 ft in a furlong and 2 weeks or 1209600 seconds in a fortnight
Multiply 537,600furlong and 660 ft/furlong and divide by 1209600 to get 293.333ft/s
The race car is already in ft/s
There are 30.48 cm in 1 foot and 3600 seconds in 1 hour. Multiply 9,000,000 by 1/30.48 and 1/3600 to get 82.02ft/s
THe peregrine falcon is the fastest
The width of the cuvette is important in the spectrophotometric analysis since wider cuvette<span> translates to more absorbing species present in the path where light passes, hence more absorbance is read in the analysis. other factors include the concentration of the sample and the species itself present.</span>
Answer:
thats pink floyds album cover LOL
but the answer is to prism
hope this helps :)
1.205 × 10²³ atoms of oxygen will be present in 7.51 grams of glycine with formula C₂H5O2N. Details about number of atoms can be found below.
How to calculate number of atoms?
The number of atoms of a substance can be calculated by multiplying the number of moles of the substance by Avogadro's number.
However, the number of moles of oxygen in glycine can be calculated using the following expression:
Molar mass of C₂H5O2N = 75.07g/mol
Mass of oxygen in glycine = 32g/mol
Hence; 32/75.07 × 7.51 = 3.2grams of oxygen in glycine
Moles of oxygen = 3.2g ÷ 16g/mol = 0.2moles
Number of atoms of oxygen = 0.2 × 6.02 × 10²³ = 1.205 × 10²³ atoms
Therefore, 1.205 × 10²³ atoms of oxygen will be present in 7.51 grams of glycine with formula C₂H5O2N.
Learn more about number of atoms at: brainly.com/question/8834373
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