Answer:
Option B
Lockout/ Tagout
Explanation:
lockout and tagout is a safety procedure used in most industries and work places. This ensures that during any maintenance work, that dangerous machines are properly shut off and not able to be started up again prior to the completion of maintenance or repair work.
The procedure includes:
1. Turns off and disconnects the machinery or equipment from its energy source(s) before performing service or maintenance.
2. The authorized employee(s) either lock or tag the energy-isolating device(s) to prevent the release of hazardous energy.
Answer: you can watch a video on how to solve this question on you tube
The acceleration at points A, B and C are respectively; 960 mm²/s, 1600 mm²/s and 600 mm²/s
<h3>What is the acceleration?</h3>
The drum rolls without sliding and as such its' instantaneous center will lie at B. Thus;
V_d = V_c = 160 mm/s
Also, a_d = a_c = 600 mm²/s
Now, formula for velocity at A is;
V_a = r_ab * ω
where ω = 160/(100 - 60)
ω = 4 rad/s
V_a = 60 * 4
V_a = 240 mm/s
Acceleration at A = V_a²/r_ab
Acceleration at A = 240²/60 = 960 mm²/s
Now, V_b = 100 * 4 = 400 mm/s
Acceleration at B = 400²/100 = 1600 mm²/s
Read more about Acceleration at; brainly.com/question/14344386
Answer:
Starting current
Explanation:
The motor branch circuit short circuit and ground-fault protective device shall be capable of carrying the <u>Starting current</u> of the motor.
