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DiKsa [7]
4 years ago
15

Which example is most likely an inorganic compound? A. methane, which is made of carbon and hydrogen B. glucose, which is a suga

r made by plants C. sodium chloride, which is a salt D. human DNA, which is a molecule in cells
Chemistry
2 answers:
Wittaler [7]4 years ago
7 0

Answer:

The correct answer is C (sodium chloride which is a salt human)

Explanation:

The sodium chloride whose formula is NaCl, corresponds to an ionic compound formed by a metal (Na) and a nonmetal (Cl). It corresponds to an inorganic substance, since it does not have carbon. Organic compounds are those that have carbon (example: glucose, methane, etc.)

Ilya [14]4 years ago
3 0

Answer:

The correct answer is C (sodium chloride which is a salt human)

Explanation:

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(03.01 LC<br> Which of the following is not present in an atom? (1 point)
yulyashka [42]

Answer:

Protons, Neutrons, and Electrons are all in atoms so the one not present would be the Element since Elements are made of atoms.

Explanation:

4 0
3 years ago
How many moles of aluminum oxide al2o3 are in a sample with a mass of 204.0
erik [133]

Answer:

2 moles

Explanation:

Let us first start by calculating the molecular mass of Al₂O₃.

The mass of a mole of any compound is called it's molar mass. 1 molar mass 6.02 X 10²³, or Avogadro's number, of compound entities.

Say, 1 mole of Al₂O₃ has 6.02 X 10²³ of Al₂O₃ molecules/atoms. It also has 2*6.02 X 10²³ number of Al atoms and 3*6.02 X 10²³ number of O atoms.

Molecular mass of Al : 26.981539 u

Molecular mass of O: 15.999 u

Therefore, molecular mass of Al₂O₃ is:

= (2*26.981539) + (3*15.999) u

= 101.960078 u

This can be approximated to 102 u.

1mole weighs 102 u

So, 2moles will weigh 2*102 = 204 u

3 0
3 years ago
Read 2 more answers
Not a timed or graded assignment. Please show all calculation work. Question prompt : “what mass of the excess reactant will get
Vikki [24]

1) Balance the chemical equation

CaCO_3+2HCl\rightarrow CaCl_2+H_2O+CO_2

2) Convert grams to moles.

The molar mass of CaCO3 is 100.086 g/mol

molCaCO_3=10.0gCaCO_3*\frac{1molCaCO_3}{100.086gCacO_3}=0.0999molCaCO_3

We have 0.0999 mol CaCO3.

The molar mass of HCl is 36.46 g/mol

molHCl=15.0gHCl*\frac{1molHCl}{36.456gHCl}=0.411molHCl

We have 0.411 mol HCl.

3) Which is the limiting reactant?

How many moles of CaCO3 do we need to use all of the HCl?

The molar ratio between CaCO3 and HCl is 1 mol CaCO3: 2 mol HCl.

molCaCO_3=0.411molHCl*\frac{1molCaCO_3}{2molHCl}=0.2055molCaCO_3

<em>We need 0.2055mol CaCO3 and we have 0.0999mol CaCO3. We do not have enough CaCO3. This is the limiting reactant.</em>

How many moles of HCl do we need to use all of the CaCO3?

The molar ratio between CaCO3 and HCl is 1 mol CaCO3: 2 mol HCl.

molHCl=0.0999molCaCO_3*\frac{2molHCl}{1molCaCO_3}=0.1998molHCl

<em>We need 0.1998mol HCl and we have 0.411 mol HCl. We have enough HCl. This is the excess reactant.</em>

4) What mass of the excess reactant will get used?

We have 0.411 mol HCl

We need 0.1998 mol HCl. This is what we will use.

5) Convert moles to grams

The molar mass of HCl is 36.46 g/mol

gHCl=0.1998molHCl*\frac{36.46gHCl}{1molHCl}=7.285gHCl

<em>7.28g HCl will get used in the reaction.</em>

.

5 0
2 years ago
A. How many moles of ammonium sulfate will be produced with 25.56 grams of ammonia gas
Irina-Kira [14]
I do not know do you?
3 0
3 years ago
For each mole of glucose (C6H12O6) completely oxidized by cellular respiration, how many moles of CO2 are released in the citric
topjm [15]

Answer:

4  

Step-by-step explanation:

The reactions are:

Glycolysis:                      1 glucose ⟶ 2 pyruvate

Link reaction:         2 × [1 pyruvate ⟶ 1 acetyl CoA]

Citric acid cycle: 2 × [1 AcetylCoA ⟶ 2 CO₂]

Now, add the reactions, cancelling species that occur on both sides of the reaction arrow,

             1 glucose ⟶ <u>2 pyruvate </u>

           <u>2 pyruvate</u> ⟶ <u>2 acetyl CoA </u>

        <u>2 AcetylCoA </u>⟶ 4 CO₂

<em>Overall</em> : 1 glucose ⟶ 4 CO₂

For each mole of glucose, four molecules of CO₂ are released in the citric acid cycle.

4 0
3 years ago
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