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Salsk061 [2.6K]
2 years ago
11

Explain what happens to the energy in a wave when a sound is louder.

Chemistry
1 answer:
liraira [26]2 years ago
8 0
Greater amplitude waves have more energy and greater intensity, so they sound louder. ... The same amount of energy is spread over a greater area, so the intensity and loudness of the sound is less. This explains why even loud sounds fade away as you move farther from the source.
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Equation for the reaction btn nitric acid and metal X whose valence is 3​
viva [34]
(a) Reaction of nitric acid with non-metal:
C+4HNO
3
​
⟶CO
2
​
+2H
2
​
O+4NO
2
​

S+6HNO
3
​
⟶H
2
​
SO
4
​
+2H
2
​
O+6NO
2
​

(b) Nitric acid showing acidic character:
K
2
​
O+2HNO
3
​
⟶2KNO
3
​
+H
2
​
O
ZnO+2HNO
3
​
⟶Zn(NO
3
​
)
2
​
+H
2
​
O
(c) Nitric acid acting as oxidizing agent
P
4
​
+20HNO
3
​
⟶4H
3
​
PO
4
​
+4H
2
​
O+20NO
2
​

3Zn+8HNO
3
​
⟶3Zn(NO
3
​
)
2
​
+4H
2
​
O+2NO

hope that helps you please mark brainliest
3 0
2 years ago
The rate constant of a certain reaction is known to obey the Arrhenius equation, and to have an activation energy . If the rate
vovangra [49]

Answer:

K2 = 61.2 M^-1.S^-1

Explanation:

We complete the question fully:

The rate constant of a certain reaction is known to obey the Arrhenius equation, and to have an activation energy Ea = 71.0kJ/mol . If the rate constant of this reaction is 6.7M^(-1)*s^(-1) at 244.0 degrees Celsius, what will the rate constant be at 324.0 degrees Celsius?

Answer is as follows:

The question asks us to calculate the value of the rate constant at a certain temperature, given that it is at a particular value for a particular temperature. We solve the question as follows:

According to Arrhenius equation, the relationship between temperature and activation energy is as follows:

            k = Ae^-(Ea/RT)

where,   k = rate constant

              A = pre-exponential factor

          Ea  = activation energy

             R = gas constant

              T = temperature in kelvin

From the equation, the following was derived for a double temperature problem:

ln(k2/k1) = (-Ea/R) * (1/T1 - 1/T2)

We list out the parameters as follows:

         

      T1= (244 + 273.15) K = 517.15 K

      T2= (324+ 273.15) K =597.15 K

    K1  = 6.7 ,     K2 = ?

         R = 8.314 J/mol K

     Ea = 71.0 kJ/mol = 71000 J/mol

Putting the given values into the above formula as follows:

ln(k2/6.7) = (-71000/8.314) * (1/517.15 - 1/597.15)

lnk2 - 1.902 = 8539.8 * 0.000259

lnK2 = 1.902 + 2.21

lnK2 = 4.114

K2 = e^(4.114)

K2 = 61.2

Hence, K2 = 61.2 (M.S)^-1

7 0
3 years ago
Read 2 more answers
Calculate the density of the items below. (D = M/V)<br> 1) M = 15g V = 5.0ml *
grin007 [14]

Answer:

<h3>The answer is 3.0 g/mL</h3>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question

mass = 15 g

volume = 5 mL

We have

density =  \frac{15}{5}  \\

We have the final answer as

<h3>3.0 g/mL</h3>

Hope this helps you

5 0
2 years ago
Jerry listed the following process on his notebook:
topjm [15]

Answer:

2

Explanation:

1. The dew is formed when the water vapor at the atmosphere contacts the leaves, which are at a low temperature, so, the vapor temperature decreases, and the liquid is formed. So, it's a gas to liquid change.

2. Ice cubes are at the solid-state, thus this transformation is solid to a liquid change.

3. The cold juice is at a low temperature, so when the water vapor of the air contacts with the glass, its temperature decreases, and its change to a liquid phase. So, it's a gas to liquid change.

4. The evaporated water from the Earth's surface goes to the atmosphere, and, at high altitudes, the temperature is low, so the water vapor condenses and the drops get closer together forming the clouds. So, it's a gas to a liquid change.

5 0
2 years ago
Which product of petroleum is normally used as fuel in cars and light vehicles​
Elena L [17]

Answer:

mostly gasoline in cars nowadays

8 0
3 years ago
Read 2 more answers
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