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solong [7]
3 years ago
11

A pickup truck starts from rest and maintains a constant acceleration a0. After a time t0, the truck is moving with speed 25 m/s

at a distance of 120 m from its starting point. When the truck has travelled a distance of 60 m from its starting point, its speed is v1 m/s.
Which of the following statements concerning v1 is true?
a. v1< 12.5m/s
b. v1= 12.5m/s
c. v1 >12.5m/s
Physics
1 answer:
MA_775_DIABLO [31]3 years ago
7 0

Answer:

B v1= 12.5m/s

Explanation:

As the acceleration is constant and time taken is also same and distance covered is halfed so the speed will also be halfed.

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What is Parabolic flight
blagie [28]
This aircraft is used to train astronauts in zero-g maneuvers, giving them about 25 seconds of weightlessness out of 65 seconds of flight<span> in each </span>parabola<span>. During such training, the airplane typically flies about 40–60 </span>parabolic<span> maneuvers</span>
3 0
3 years ago
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What is the mass in rams of 30.00 ml of a liquid that has a density of 1.21 g/ml?
Murljashka [212]

Answer:

36.3 g

Explanation:

 1.21  g/ml  *  30 ml   = 36.3 g     ( see how the 'ml' units cancel ?)

3 0
2 years ago
The asteroid belt circles the sun between the orbits of Mars and Jupiter. One asteroid has a period of 5.4 earth years.
Ad libitum [116K]

Answer:

(a) Radius = 4.6 x 10^11 m

(b) speed = 16.96 km/s

Explanation:

Time period, T = 5.4 earth years

mass of sun, M = 1.989 x 10^30 kg

(a) Let the orbital radius is R.

use the formula of period

T^2 = \frac{4 \pi^2 R^3}{G M}\\\\\left ( 5.4\times 365\times 24\times 3600 \right )^2 = \frac{4\times3.14\times 3.14\times R^3}{6.67\times10^{-11}\times 1.989\times 10^{30}}\\\\R = 4.6\times 10^{11} m

(b) Let the speed is v.

v=\frac{2 \pi\times R}{T}\\\\v=\frac{2\times 3.14\times 4.6\times 10^{11}}{5.4\times 365\times 24\times 3600}\\\\v = 16963.6 m/s =16.96 km/s

3 0
2 years ago
Kieran takes off from rest down a 50 m high, 10° slope on his jet-powered skis. The skis have a thrust of 280 N parallel to the
xz_007 [3.2K]

Answer:0.46

Explanation:

Given

Initial height h=50 m

inclination \theta =10^{\circ}

Thrust=280 N

combined mass of kieran and skis m=50 kg

Speed at the bottom v=40 m/s

From Work Energy Theorem

Work done by all the force is equal to change in kinetic Energy

W_{gravity}+W_{friction}+W_{thrust}=\frac{1}{2}mv^2-0------------1

distance traveled along the slope x=\frac{50}{\sin 10}=287.93 m

W_{gravity}=mgh=50\times 9.8\times 50=24500 J

W_{thrust}=F\times x=280\times 287.93=80,620.4 J

W_{friction}=-\mu mg\cos 10

substitute in 1

24,500+80,620.4+W_{friction}=\frac{1}{2}\times 50\times 1600

W_{friction}=40,000-24,500-80,620.4

-\mu \cdot 50\times 9.8\times 287.93=-65,120.4

\mu =\frac{65,120.4}{141,085.7}=0.46

8 0
3 years ago
Tell whether the following statements are true or false:
Digiron [165]

Answer:

1)true

2)false

3)true

4)true

5)false,cz amatter is made of atoms while light is an electromagnetic radiation.

8 0
3 years ago
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