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Flura [38]
2 years ago
5

Why do most carnivores live in forest? given reason ​

Physics
2 answers:
dem82 [27]2 years ago
6 0

1) Carnivores live in forests because it an ideal habitat for them and they prey they hunt. Carnivores feed on herbivores, and they feed on plants. Forests also contain many species of insects which are also among the prey of smaller predators.

2) Carnivores are animals that eat other animals. Their presence in the forest is essential for three reasons: They help in transferring energy from one trophic level to another in a food chain. i.e they transfer the energy stored in the animal they eat into themselves to the next level who consume them.

kotegsom [21]2 years ago
3 0

\huge\purple{Hi!}

most carnivore live in forest because

  1. They are highly dependent on flesh for their food and therefore their food is easily available in forests.
  2. Small animals live in forests that make it the ideal habitat for carnivores.
  3. Carnivores help in maintaining the herbivore population at a healthy level, by hunting.
  4. It all helps in keeping ecosystems in balance.

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The half-life for a 100-gram sample of radioactive element X is 5 days. How much of element X remains after 10 days have passed?
pav-90 [236]

Answer:

25g

Explanation:

Given parameters:

    Half life of X = 5days

Mass of sample of radioactive elements  = 100g

The half-life of a radioactive material is the time it takes for a sample to decay by half. At the half-life, an original sample would have yielded equal daughter to parent ratio.

 At time (days)            Mass of sample

      0                                 100g

     5                                    50g

    10                                    25g

Every 5 days, the sample will split into half.

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3 0
3 years ago
You find a bag labeled "10 kg of lead-210". Its contents now weigh 1.25 kg. How many half-life periods have there been since the
zlopas [31]

Answer : The number of half-life periods will be, 3

Explanation :  Given,

Initial amount of lead = 10 kg

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Formula used :

a=\frac{a_o}{2^n}

where,

a = amount of reactant left after n-half lives

a_o = Initial amount of the reactant

n = number of half lives

t_{1/2} = half-life

Now put all the given values in the above formula, we get:

1.25=\frac{10}{2^n}

2^n=8

2^n=2^3

n=3

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4 years ago
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