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Flura [38]
1 year ago
5

Why do most carnivores live in forest? given reason ​

Physics
2 answers:
dem82 [27]1 year ago
6 0

1) Carnivores live in forests because it an ideal habitat for them and they prey they hunt. Carnivores feed on herbivores, and they feed on plants. Forests also contain many species of insects which are also among the prey of smaller predators.

2) Carnivores are animals that eat other animals. Their presence in the forest is essential for three reasons: They help in transferring energy from one trophic level to another in a food chain. i.e they transfer the energy stored in the animal they eat into themselves to the next level who consume them.

kotegsom [21]1 year ago
3 0

\huge\purple{Hi!}

most carnivore live in forest because

  1. They are highly dependent on flesh for their food and therefore their food is easily available in forests.
  2. Small animals live in forests that make it the ideal habitat for carnivores.
  3. Carnivores help in maintaining the herbivore population at a healthy level, by hunting.
  4. It all helps in keeping ecosystems in balance.

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Which is a key criterion for the design of an automobile bumper?
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Answer: The answer is A

Explanation: The bumper is the first part of an automobile to be impacted when in a head-on accident

3 0
3 years ago
A good refrigerant must have a high boiling point. Question 5 options: True False
Liono4ka [1.6K]

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5 0
3 years ago
Read 2 more answers
Two particles oscillate in simple harmonic motion along a common straight-line segment of length 1.0 m. Each particle has a peri
igor_vitrenko [27]

Answer:

a) the particles are <em>0.217 m </em>apart

b) <em>the particles are moving in the same direction</em>.

Explanation:

a) The amplitude of the oscillations is A/2 and the period of each particle is

T = 1.5 s however, they differ by a phase of π/6 rad. Let the phase of the first particle be zero so that the phase of the second particle is π/6. So we can write the coordinates of each of the particles as,

x₁ = A/2 cos(ωt)

x₂ = A/2 cos(ωt + π/6)

we can write the angular frequency ω, as

ω = 2π / T

so,

x₁ = A/2 cos(2π / T)

x₂ = A/2 cos(2π / T + π/6)

Thus, the coordinates of the particles at t = 0.45 s are,

x₁ = A/2 cos((2π × 0.45) / 1.5)) = -0.155 A

x₂ = A/2 cos((2π × 0.45) / 1.5) + π/6) = -0.372 A

Their separation at that time is, therefore,

Δx = x₁ - x₂

    = -0.155 A + 0.372 A

    = 0.217 A

since A = 1 m

Thus,

<em>Δx  = 0.217 m</em>

<em></em>

<em></em>

b) In order to find their directions, we must take the derivatives at t = 0.45 s.

Therefore,

v₁ = dx₁ / dt

   = (-πA / T) sin(2πt / T)

   = -(π(1) / 1.5) sin(2π(0.45) / 1.5)

   = -1.99

and,

v₂ = dx₂ / dt

   = (-πA / T) sin((2πt / T) + π/6)

   = -(π(1) / 1.5) sin((2π(0.45) / 1.5) + π/6)

   = -1.40

Since both v₁ and v₂ are negative, this shows that <em>the particles are moving in the same direction</em>.

6 0
3 years ago
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garri49 [273]

Answer:

2 m/s^2

Explanation:

a = v^2/r

a = (10m/s)^2 / 50m

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Leave a like and mark brainliest if this helped

Leave a like and mark brainliest if this helped

5 0
3 years ago
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