All categories

2 years ago

Why do most carnivores live in forest? given reason

2 answers:

6 0

1) Carnivores live in forests because it an ideal habitat for them and they prey they hunt. Carnivores feed on herbivores, and they feed on plants. Forests also contain many species of insects which are also among the prey of smaller predators.

2) Carnivores are animals that eat other animals. Their presence in the forest is essential for three reasons: They help in transferring energy from one trophic level to another in a food chain. i.e they transfer the energy stored in the animal they eat into themselves to the next level who consume them.

kotegsom [21]2 years ago

3 0

$\huge\purple{Hi!}$

most carnivore live in forest because

They are highly dependent on flesh for their food and therefore their food is easily available in forests.
Small animals live in forests that make it the ideal habitat for carnivores.
Carnivores help in maintaining the herbivore population at a healthy level, by hunting.
It all helps in keeping ecosystems in balance.

You might be interested in

Which of these is NOT a possible type of energy transformation?

Orlov [11]

to be franc i really think the answer is B

6 0

3 years ago

Which factor is the most imortant in performing the activities of daily living

wariber [46]

Answer:

Muscular endurance is the most important factor in performing the activities of daily living.

7 0

4 years ago

Heat energy is:

Archy [21]

I claim that it's d moving electrons.

6 0

3 years ago

A capacitor consists of two parallel plates, each with an area of 17.0 cm2 , separated by a distance of 0.150 cm . The material

Llana [10]

Answer:

a) $C = 40.138\,pF$ , b) $q = 16.056\,nC$ , c) $U = 3.212\,\mu J$

Explanation:

a) The capacitance of two parallel plates capacitor with dielectric is given by the following expression:

$C = K\cdot \epsilon_{o}\cdot \frac{A}{d}$

Where:

$K$ - Dielectric constant.

$\epsilon_{o}$ - Vaccum permitivity.

$A$ - Plate area.

$d$ - Distance between plates.

Hence, the capacitance of the system is:

$C = (4.00)\cdot (8.854\times 10^{-12}\,\frac{F}{m} )\cdot \left(\frac{17\times 10^{-4}\,m^{2}}{0.150\times 10^{-2}\,m}\right)$

$C = 4.014\cdot 10^{-11}\,F$

$C = 40.138\,pF$

b) The charge can be found by using the definition of capacitance:

$q = C\cdot V_{batt}$

$q = (4.014\times 10^{-11}\,F)\cdot (400\,V)$

$q = 1.606\times 10^{-8}\,C$

$q = 16.056\,nC$

c) The energy stored in the charged capacitor is:

$U=\frac{1}{2}\cdot Q\cdot V_{batt}$

$U=\frac{1}{2}\cdot (1.606\times 10^{-8}\,C)\cdot (400\,V)$

$U = 3.212\times 10^{-6}\,J$

$U = 3.212\,\mu J$

3 0

3 years ago

Read 2 more answers

A long straight wire carries a conventional current of 0.7 A. What is the approximate magnitude of the magnetic field at a locat

vfiekz [6]

Answer:

2.64 x 10⁻⁶T

Explanation:

The magnitude of the magnetic field produced by a long straight wire carrying current is given by Biot-Savart law as follows: "The magnetic field strength is directly proportional to the current on the wire and inversely proportional to the distance from the wire". This can be written mathematically as;

B = (μ₀ I) / (2π r) ----------------(i)

B is magnetic field

I is current through the wire

r is the distance from the wire

μ₀ is the magnetic constant = 4π x 10⁻⁷Hm⁻¹

From the question;

I = 0.7A

r = 0.053m

Substitute these values into equation (i) as follows;

B = (4π x 10⁻⁷ x 0.7) / (2π x 0.053)

B = 2.64 x 10⁻⁶T

Therefore the approximate magnitude of the magnetic field at that location is 2.64 x 10⁻⁶T

5 0

3 years ago

Why do most carnivores live in forest? given reason ​

Why do most carnivores live in forest? given reason