12m S=0m E, -12m N
15m 55d E of N = 15 sin 55, 15 cos 55 N
Sum= (15sin55)m E, (-12 + 15 cos 55)m N
Because of the hint we can conclude what equation we need to solve this problem. We have power and duration that means that we need to express energy:
1 joule = 1watt * 1 second
or
E (energy) = P (power) * t (time duration)
E = 350 * 30 = 10500 joules.
<h2>Answer: about the same size of the gap or slit</h2>
Diffraction happens when a wave (mechanical or electromagnetic wave, in fact, any wave) meets an obstacle or a slit .When this occurs, the wave bends around the corners of the obstacle or passes through the opening of the slit that acts as an obstacle, forming multiple patterns with the shape of the aperture of the slit.
Note that the principal condition for the occurrence of this phenomena is that the obstacle must be comparable in size (similar size) to the size of the wavelength.
In other words, when the gap (or slit) size is larger than the wavelength, the wave passes through the gap and does not spread out much on the other side, but when the gap size is equal to the wavelength, maximum diffraction occurs.
Therefore:
<h2>Waves diffract the most when their wavelength is <u>about the same size of the gap
</u></h2>
<u />
Explanation :
It is given that :
The initial velocity of the car is 10 m/s.
Juliette sets the acceleration to zero.
We know that, acceleration 
\
where,
u is the initial velocity and v is the final velocity.
So, final velocity will become 10 m/s.
Hence, the car will move with the constant velocity i.e. 10 m/s.
So, Shakina described that the car will move with the constant velocity of 10 m/s as acceleration is zero.
