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Anna35 [415]
3 years ago
10

Light incident on a Surface at an angle of 45° undergoes diffused reflection. At what angle will it reflect?

Physics
2 answers:
DanielleElmas [232]3 years ago
4 0

Answer:

0 degree to 180 degree

Explanation:

When a ray of light falls on a smooth and polished surface, then after striking it bounce back into the same medium, it is called reflection.

There are two types of reflection.

1. Regular or specular reflection: When some parallel rays incident on the smooth surface then after reelection, the reflected rays are also parallel to to each other, it is called regular reflection. In case of mirrors, the regular reflection takes place.

2. Diffused reflection: When some parallel rays falls on rough and unpolished surface, then after reflection, they are not parallel to each other.

The angle of incidence is 45 degree, in case of diffused reflection , the angle of reflection is some where between 0 degree and 180 degree.

zhuklara [117]3 years ago
3 0
The angle(s) that it will reflect will be at any angle between -90° and 90. The correct answer between all the choices given is the fourth choice or letter D. Lmk if this is correct
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A frog can be many different colours. It appears green under normal 'white' light because it absorbs all the other colours in the light's spectrum apart from green. It reflects the green light back and that is picked up by your eye.

If the light is red, there is no green in the spectrum of the light, only red. So, the red light will be absorbed and there is no green to be reflected back for you to see. Therefore, the frog will not look green.
8 0
3 years ago
Two identical trucks have mass 5100 kg when empty, and the maximum permissible load for each is 8000 kg. the first truck, carryi
Oksanka [162]
<span>The 2nd truck was overloaded with a load of 16833 kg instead of the permissible load of 8000 kg. The key here is the conservation of momentum. For the first truck, the momentum is 0(5100 + 4300) The second truck has a starting momentum of 60(5100 + x) And finally, after the collision, the momentum of the whole system is 42(5100 + 4300 + 5100 + x) So let's set the equations for before and after the collision equal to each other. 0(5100 + 4300) + 60(5100 + x) = 42(5100 + 4300 + 5100 + x) And solve for x, first by adding the constant terms 0(5100 + 4300) + 60(5100 + x) = 42(14500 + x) Getting rid of the zero term 60(5100 + x) = 42(14500 + x) Distribute the 60 and the 42. 60*5100 + 60x = 42*14500 + 42x 306000 + 60x = 609000 + 42x Subtract 42x from both sides 306000 + 18x = 609000 Subtract 306000 from both sides 18x = 303000 And divide both sides by 18 x = 16833.33 So we have the 2nd truck with a load of 16833.33 kg, which is well over it's maximum permissible load of 8000 kg. Let's verify the results by plugging that mass into the before and after collision momentums. 60(5100 + 16833.33) = 60(21933.33) = 1316000 42(5100 + 4300 + 5100 + 16833.33) = 42(31333.33) = 1316000 They match. The 2nd truck was definitely over loaded.</span>
6 0
3 years ago
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notsponge [240]

Answer:

E=-1.51 eV.

L=\hbar\sqrt{2}

Explanation:

The nth level energy of a hydrogen atom is defined by the formula,

E_{n}=-\frac{13.6}{n^{2} }

Given in the question, the hydrogen atom is in the 3p state.

Then energy of n=3 state is,

E_{n}=-\frac{13.6}{(3)^{2} }\\E_{n}=-1.51eV

Therefore, energy of the hydrogen atom in the 3p state is -1.51 eV.

Now, the value of L can be calculated as,

L=\hbar\sqrt{l(l+1)}

For 3p state, l=1

L=\hbar\sqrt{1(1+1)}\\L=\hbar\sqrt{2}

Therefore, the value of L of a hydrogen atom in 3p state is L=\hbar\sqrt{2}.

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Answer:

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During the Prophase

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Sound waves need different media in order to travel. This travels by the movement of the atom transferred to another up to its destination. The speed of sound is greatest in solids since the molecules of solid are closely packed together, followed by liquid and they are slowest in gases. 
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