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Anna35 [415]
3 years ago
10

Light incident on a Surface at an angle of 45° undergoes diffused reflection. At what angle will it reflect?

Physics
2 answers:
DanielleElmas [232]3 years ago
4 0

Answer:

0 degree to 180 degree

Explanation:

When a ray of light falls on a smooth and polished surface, then after striking it bounce back into the same medium, it is called reflection.

There are two types of reflection.

1. Regular or specular reflection: When some parallel rays incident on the smooth surface then after reelection, the reflected rays are also parallel to to each other, it is called regular reflection. In case of mirrors, the regular reflection takes place.

2. Diffused reflection: When some parallel rays falls on rough and unpolished surface, then after reflection, they are not parallel to each other.

The angle of incidence is 45 degree, in case of diffused reflection , the angle of reflection is some where between 0 degree and 180 degree.

zhuklara [117]3 years ago
3 0
The angle(s) that it will reflect will be at any angle between -90° and 90. The correct answer between all the choices given is the fourth choice or letter D. Lmk if this is correct
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Which electrode in Thomson’s vacuum tube was positively charged
Taya2010 [7]

Anode

Explanation:

The anode in the gas discharge tube used by Thomson in his experiment was the positively charged electrode.

Using the gas discharge tube, Thomson made the remarkable discovery of cathode rays.

The rays moves from the negatively charged cathode to the positively charged anode. This indicated that the rays carry positive charges.

Some parts of the tube are:

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8 0
3 years ago
A geologist is studying rock layers in an old river bed, and he finds a fossil of a fish and a horsetail rush in the same rock l
KonstantinChe [14]
A geologist is studying rock layers in an old river bed, and he finds a fossil of a fish and a horsetail rush in the same rock layer. According to the law of faunal and floral succession, the geologist can assume that the rock containing the fossils may date back as far as the <span>Devonian period</span>.
6 0
3 years ago
Read 2 more answers
A stubborn, 100 kgkg mule sits down and refuses to move. To drag the mule to the barn, the exasperated farmer ties a rope around
jolli1 [7]

Answer:

No, the farmer is not able to move the mule.

Explanation:

Mass =100 kg

Force=F=800 N

The coefficient between the mule and the ground=\mu_s=0.8

\mu_k=0.5

Static friction force,f=\mu N

Normal force=N=mg

Static friction force,f=\mu_s mg=0.8\times 100\times 9.8=784 N

Using g=9.8m/s^2

F<f

Static friction force is greater than applied force.

Therefore , the farmer is not able to move the mule.

4 0
3 years ago
You stand on a merry-go-round which is spinning at f = 0.25 revolutions per second. You are R = 200 cm from the center. (a) Find
wariber [46]

Answer:

a) ω = 9.86 rad/s

b) ac = 194. 4 m/s²

c) minimum coefficient of static friction, µs = 19.8

Explanation:

a) angular speed, ω = 2πf, where f is frequency of revolution

1 rps = 6.283 rad/s, π = 3.142

ω = 2 * 3.14 * 0.25 * 6.28

ω = 9.86 rad/s

b) centripetal acceleration, a = rω²

where r is radius in meters; r = 200 cm or 2 m

a = 2 * 9.86²

a = 194. 4 m/s²

c) µs = frictional force/ normal force

frictional force = centripetal force = ma; where a is centripetal acceleration

normal force = mg; where g = 9.8 m/s²

µs = ma/mg = a/g

µs = 194.4 ms⁻²/9.8 ms⁻²

c) minimum coefficient of static friction, µs = 19.8

5 0
3 years ago
Which of the following wavelengths will produce standing waves on a string that is 3.5 m long?
denpristay [2]

In a string of length L, the wavelength of the n-th harmonic of the standing wave produced in the string is given by:

\lambda=\frac{2}{n} L


The length of the string in this problem is L=3.5 m, therefore the wavelength of the 1st harmonic of the standing wave is:

\lambda=\frac{2}{1} \cdot 3.5 m=7.0 m


The wavelength of the 2nd harmonic is:

\lambda=\frac{2}{2} \cdot 3.5 m=3.5 m


The wavelength of the 4th harmonic is:

\lambda=\frac{2}{4} \cdot 3.5 m=1.75 m


It is not possible to find any integer n such that \lambda=5 m, therefore the correct options are A, B and D.

3 0
3 years ago
Read 2 more answers
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