Answer:
The mole fraction of ethanol is 0.6. A 10 mL volumetric pipette must be used for to measure the 10 mL of ethanol. The vessel should be clean and purged.
Explanation:
For calculating mole fraction of ethanol, the amount of moles ethanol must be calculated. Using ethanol density (0.778 g/mL), 10 mL of ethanol equals to 7.89 g of ethanol and in turn 0.17 moles of ethanol. The same way for calculate the amount of water moles (ethanol density=0.997 g/mL). 2 mL of water correspond to 0.11. The total moles are: 0.17+0.11=0.28. Mole fraction alcohol is: 0.17/0.28=0.6
Answer:
is it some kind of code??...........
Answer:
Explanation:
[ so₃] = 4.37 x 10⁻²
[so₂] = 4.77 x 10⁻²
[ o₂] = 4.55 x 10⁻²
Qc = (4.37)²x10⁻⁴ /(4.77)².(4.55) x 10⁻⁶ =18.44
Qc is less than Kc hence in order to reach equilibrium more of so₃ will be produced . Statement 1 is true.
Kc is always constant . Statement 2 is false.
Statement 3 is false because statement 1 is true.
Qc Is smaller than Kc . So statement 4 is false.
The reaction is not in equilibrium. Statement 5 is false.
The answer is D. This is because a synthesis reaction is when two elements combined to make a product (ex. A+B= AB). Hope this helps!
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