Dissociation of Pb₃(PO₄)₂ is;
Pb₃(PO₄)₂(s) ⇆ 3Pb²⁺(aq) + 2PO₄³⁻(aq)
initial - -
change -X +3X +2X
Equilibrium 3X 2X
Ksp = [Pb²⁺(aq)]³ [PO₄³⁻(aq)]²
1.0 x 10⁻⁵⁴ = (3X)³ (2X)²
1.0 x 10⁻⁵⁴ = 108X⁵
X = 6.21 x 10⁻¹² M
Hence the molar solubility of Pb₃(PO₄)₂ is 6.21 x 10⁻¹² M.
Answer is: <span>the pressure of the gas is 9,2 atm.
</span>p₁ = 4,0 atm.
T₁ = 300 K.
V₁ = 5,5 L.
p₂ = ?
T₂ = 250 K.
V₂ = 2,0 L.
Use combined gas law - the volume of amount of gas is proportional to the ratio of its Kelvin temperature and its pressure.<span>
</span>p₁V₁/T₁ = p₂V₂/T₂.
4 atm · 5,5 L ÷ 300 K = p₂ · 2,0 L ÷ 250 K.
0,0733 = 0,008p₂.
p₂ = 9,2 atm.
Answer:
Longer hydrocarbon molecules have a stronger intermolecular force. More energy is needed to move them apart so they have higher boiling points . This makes them less volatile and therefore less flammable
Answer:
In covalent bonding, the octet rule is important because sharing electrons gives both atoms a full valence shell. As a result, each atom can consider the shared electrons to be part of its own valence shell.
np :)
Particles below the surface of a liquid