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Fed [463]
3 years ago
8

Consider the following reaction where Kc = 34.5 at 1150 K:2SO2(g) + O2(g) 2SO3(g)A reaction mixture was found to contain 4.77×10

-2 moles of SO2(g), 4.55×10-2 moles of O2(g) and 4.37×10-2 moles of SO3(g), in a 1.00 Liter container.Indicate True (T) or False (F) for each of the following:1. In order to reach equilibrium SO3(g) must be produced.2. In order to reach equilibrium Kc must increase.3. In order to reach equilibrium SO2 must be produced.4. Qc is greater than Kc.5. The reaction is at equilibrium. No further reaction will occur.
Chemistry
1 answer:
sukhopar [10]3 years ago
3 0

Answer:

Explanation:

[ so₃] = 4.37 x 10⁻²

[so₂] = 4.77 x 10⁻²

[ o₂] = 4.55 x 10⁻²

Qc = (4.37)²x10⁻⁴ /(4.77)².(4.55) x 10⁻⁶ =18.44

Qc is less than Kc hence in order to reach equilibrium more of so₃ will be produced . Statement 1 is true.

Kc is always constant . Statement 2 is false.

Statement 3 is false because statement 1 is true.

Qc Is smaller than Kc . So statement 4 is false.

The reaction is not in equilibrium. Statement 5 is false.

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miskamm [114]

Answer:

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Explanation:

Because metal pots are made from a narrow range of metals because pots and pans need to conduct heat well.

7 0
3 years ago
What is the molar mass of (NH), CO?<br> 138g<br> 788<br> 968<br> 1448
aleksandr82 [10.1K]

Answer:

The molar mass of (NH_{4})_{2}CO_{3} is 96.8 g/mol

Explanation:

The given molecular formula - (NH_{4})_{2}CO_{3}

Individual molar masses of each element in the compound is as follows.

Molar mass of nitrogen - 14.01 g/mol

Molar mass of of hydrogen = 1.008g/mol

Molar mass of carbon = 12.01 g/mol

Molar mass of oxygen =16.00 g/mol

Molar mass of (NH_{4})_{2}CO_{3} is

2\times[1(14.01)+4(1.008)]+1(12.01)+3(16.00)= 96.8g/mol

Therefore,The molar mass of (NH_{4})_{2}CO_{3} is 96.8 g/mol

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Read 2 more answers
the combustion of a sample butane, C4H10 (lighter fluid) produced 2.46 grams of water. how many moles of water formed
enyata [817]
2C_4H_{10}+13O_2 ⇒ 8CO_2 + 10H_2O

n= \frac{m}{M} =  \frac{m}{2M(H)+M(O)}= \frac{2,46}{2*1,0+16,0}  = 0,14mol

So 0,14mol are formed.


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3 years ago
Why is it important to compare the positive and negative test results with those of known compounds?
maks197457 [2]

It is important to compare the positive and negative test results with those of known compounds as positive results indicate the presence of that known compound and negative results indicate the absence of that compound which is used for reference.

<h3>What is qualitative analysis?</h3>

Qualitative chemical analysis is a method to determine the chemical composition of a sample.

There are two types of qualitative analysis:

  • Organic Qualitative analysis: It helps in determining the chemical bonds and functional groups in a sample
  • Inorganic qualitative analysis: It helps in determining the ions in the given sample

There are seven ways to analyze a sample qualitatively, which are

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  • Flame test
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  • Extraction
  • Precipitation
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A reference compound is always used to which results are compared.

A Positive result indicates that the reference compound is present in the sample whereas a negative result indicates that the reference compound is absent in the given sample.

Learn more about qualitative analysis:

brainly.com/question/1779681

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1 year ago
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