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Fed [463]
3 years ago
8

Consider the following reaction where Kc = 34.5 at 1150 K:2SO2(g) + O2(g) 2SO3(g)A reaction mixture was found to contain 4.77×10

-2 moles of SO2(g), 4.55×10-2 moles of O2(g) and 4.37×10-2 moles of SO3(g), in a 1.00 Liter container.Indicate True (T) or False (F) for each of the following:1. In order to reach equilibrium SO3(g) must be produced.2. In order to reach equilibrium Kc must increase.3. In order to reach equilibrium SO2 must be produced.4. Qc is greater than Kc.5. The reaction is at equilibrium. No further reaction will occur.
Chemistry
1 answer:
sukhopar [10]3 years ago
3 0

Answer:

Explanation:

[ so₃] = 4.37 x 10⁻²

[so₂] = 4.77 x 10⁻²

[ o₂] = 4.55 x 10⁻²

Qc = (4.37)²x10⁻⁴ /(4.77)².(4.55) x 10⁻⁶ =18.44

Qc is less than Kc hence in order to reach equilibrium more of so₃ will be produced . Statement 1 is true.

Kc is always constant . Statement 2 is false.

Statement 3 is false because statement 1 is true.

Qc Is smaller than Kc . So statement 4 is false.

The reaction is not in equilibrium. Statement 5 is false.

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Answer:

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4 0
3 years ago
Help with this worksheet please (24pts)
Igoryamba
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  • Here, 2+ represents that Calcium (Ca) should gain 2 more electrons so that its number equals to that of protons.
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7 0
2 years ago
1. which is not a component of biodiversity
Vera_Pavlovna [14]
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8 0
3 years ago
What is the answer? <br><br> NO LINKS!!
jek_recluse [69]
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5 0
3 years ago
I need you to solve for me plzzzzzz
Sergeu [11.5K]

Answer:

.0556 L

Explanation:

First, convert the 1.35 M to 1.35 mol/L in order for the units to correctly cancel out.

Then, multiply (0.0725 moles Na2CO3/1) times (L/ 1.35 mol).

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