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Fed [463]
4 years ago
8

Consider the following reaction where Kc = 34.5 at 1150 K:2SO2(g) + O2(g) 2SO3(g)A reaction mixture was found to contain 4.77×10

-2 moles of SO2(g), 4.55×10-2 moles of O2(g) and 4.37×10-2 moles of SO3(g), in a 1.00 Liter container.Indicate True (T) or False (F) for each of the following:1. In order to reach equilibrium SO3(g) must be produced.2. In order to reach equilibrium Kc must increase.3. In order to reach equilibrium SO2 must be produced.4. Qc is greater than Kc.5. The reaction is at equilibrium. No further reaction will occur.
Chemistry
1 answer:
sukhopar [10]4 years ago
3 0

Answer:

Explanation:

[ so₃] = 4.37 x 10⁻²

[so₂] = 4.77 x 10⁻²

[ o₂] = 4.55 x 10⁻²

Qc = (4.37)²x10⁻⁴ /(4.77)².(4.55) x 10⁻⁶ =18.44

Qc is less than Kc hence in order to reach equilibrium more of so₃ will be produced . Statement 1 is true.

Kc is always constant . Statement 2 is false.

Statement 3 is false because statement 1 is true.

Qc Is smaller than Kc . So statement 4 is false.

The reaction is not in equilibrium. Statement 5 is false.

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'cause alphe-particle which was +ve charge, get repulsion from the atom, so he deducted that.......
3 0
3 years ago
A 5.024 mg sample of an unknown organic molecule containing carbon, hydrogen, and nitrogen only was burned and yielded 13.90 mg
Dafna1 [17]

Answer:

C8H17N

Explanation:

Mass of the unknown compound = 5.024 mg

Mass of CO2 = 13.90 mg

Mass of H2O = 6.048 mg

Next, we shall determine the mass of carbon, hydrogen and nitrogen present in the compound. This is illustrated below:

For carbon, C:

Molar mass of CO2 = 12 + (2x16) = 44g/mol

Mass of C = 12/44 x 13.90 = 3.791 mg

For hydrogen, H:

Molar mass of H2O = (2x1) + 16 = 18g/mol

Mass of H = 2/18 x 6.048 = 0.672 mg

For nitrogen, N:

Mass N = mass of unknown – (mass of C + mass of H)

Mass of N = 5.024 – (3.791 + 0.672)

Mass of N = 0.561 mg

Now, we can obtain the empirical formula for the compound as follow:

C = 3.791 mg

H = 0.672 mg

N = 0.561 mg

Divide each by their molar mass

C = 3.791 / 12 = 0.316

H = 0.672 / 1 = 0.672

N = 0.561 / 14 = 0.040

Divide by the smallest

C = 0.316 / 0.04 = 8

H = 0.672 / 0.04 = 17

N = 0.040 / 0.04 = 1

Therefore, the empirical formula for the compound is C8H17N

8 0
3 years ago
2. Solid sodium reacts with gaseous chlorine to produce sodium chloride.
stich3 [128]
2Na (s) + Cl2 (g) = 2NaCl (s)
8 0
3 years ago
Why is there a bond between the ions in potassium chloride
yKpoI14uk [10]

Answer:

Explanation:

When the two atoms are in contact, potassium transfers its outer electron to chlorine which readily accepts it, resulting in both atoms achieving a state of eight outermost electrons. With this electron transfer, the ionic bond in KCl is formed.

Hope this helped!!!

6 0
3 years ago
Which of the following are present both before and after a chemical reaction?
Harrizon [31]
That would be a catalyst, it makes the reaction faster.
5 0
3 years ago
Read 2 more answers
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