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PIT_PIT [208]
3 years ago
10

Janice ran a 5 km race on Saturday at 0.75 h. What was her speed? HELP MEHHH NOWWWW

Chemistry
2 answers:
a_sh-v [17]3 years ago
4 0
Speed=distance/time. S=5km/.75 h=6.67 kmh
ryzh [129]3 years ago
3 0

Answer

A runner ran 20 miles in 150 minutes. If she runs at that ... run in 15 minutes? How fast is she running in miles per hour? What is her pace in minutes per mile?

Explanation:

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What impact can limiting factors have on a population?
Salsk061 [2.6K]

Answer:

The answer is B. Limiting factors can lower birth rates, increase death rates.

7 0
2 years ago
Read 2 more answers
What is the mass of 7 x 10^28 atoms of Fe?
Nostrana [21]

Answer:

6 x 10⁶ g Fe

Explanation:

Step 1: Set up dimensional analysis

7 x 10²⁸ atoms Fe (1 mol Fe/6.02 x 10²³ atoms Fe)(55.85 g Fe/1 mol Fe)

Step 2: Multiply, divide, and cancel out units

atoms Fe and atoms Fe cancel out.

mol Fe and mol Fe cancel out.

We should be left with g Fe.

7 x 10²⁸/6.02 x 10²³ = 116279 mol Fe

116279(55.85) = 6.49 x 10⁶ g Fe

Step 3: Sig figs

There is only 1 sig fig in this problem.

6.49 x 10⁶ g Fe ≈ 6 x 10⁶ g Fe

4 0
3 years ago
The process of gas converting to a liquid is called evaporation.<br><br> TRUE<br><br> FALSE
motikmotik
False. Because gas to a liquid is called condensation
6 0
3 years ago
Is an oreo a pure substance or a mixture and why?
pav-90 [236]
Pure oreo would be a mixture 
7 0
4 years ago
Average Molarity for HCl is .391
Ira Lisetskai [31]

Answer:

#1: 0.00144 mmolHCl/mg Sample

#2: 0.00155 mmolHCl/mg Sample

#3: 0.00153 mmolHCl/mg Sample

Explanation:

A antiacid (weak base) will react with the HCl thus:

Antiacid + HCl → Water + Salt.

In the titration of antiacid, the strong acid (HCl)  is added in excess, and you're titrating with NaOH moles of HCl that doesn't react.

Moles that react are the difference between mmoles of HCl - mmoles NaOH added (mmoles are Molarity×mL added). Thus:

Trial 1: 0.391M×14.00mL - 0.0962M×34.26mL = 2.178 mmoles HCl

Trial 2: 0.391M×14.00mL - 0.0962M×33.48mL = 2.253 mmoles HCl

Trial 3: 0.391M×14.00mL - 0.0962M×33.84mL = 2.219 mmoles HCl

The mass of tablet in mg in the 3 experiments is 1515mg, 1452mg and 1443mg.

Thus, mmoles HCl /mg OF SAMPLE<em> </em>for each trial is:

#1: 2.178mmol / 1515mg

#2: 2.253mmol / 1452mg

#3: 2.219mmol / 1443mg

<h3>#1: 0.00144 mmolHCl/mg Sample</h3><h3>#2: 0.00155 mmolHCl/mg Sample</h3><h3>#3: 0.00153 mmolHCl/mg Sample</h3>
8 0
3 years ago
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