Ionic bonds happen when Metals give electron to non-metals and covalent bonds happen when Non-metals give electrons away. Knowing this:
-NaF = ionic (Na is a metal, F is a non-metal)
-NF3 = Covalent (N is a non-metal, F is a non-metal)
-SiF4 = Ionic (Si is a metalloid, F is non-metal)
-CaF2 = ionic (Ca is a metal, F is a non-metal)
-NH4F = covalent (N is a non-metal, H is a non-metal, F is a non-metal)
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The lowest smallest whole-number coefficient for H₂S is 5. Option C
<h3>What is the smallest whole-number coefficient for H₂S?</h3>
Now we know that a redox reaction is one in which there is a loss and gain of electrons One specie is oxidized (looses electrons) while another specie is reduced (gains electrons). The electrons must be transferred leading to an increase in oxidation number of one specie and a decrease in the oxidation number of another.
Now the reduction half equation is;
MnO4^-(aq) + 8H^+(aq) + 5e^- ----> Mn^2+(aq) + 4H2O (l)
The oxidation half equation is;
H2S(aq) ----> S^2-(aq) + 2H^+(aq) + 2e^-
Multiplying the reduction half equation by 2 and the oxidation half equation is 5
2MnO4^-(aq) + 16H^+(aq) + 10e^- ----> 2Mn^2+(aq) + 8H2O (l)
And;
5H2S(aq) ----> 5S^2-(aq) + 10H^+(aq) + 10e^-
The overall balanced reaction equation is;
2MnO4^-(aq) + 6H^+(aq) + 5H2S(aq) ----> 2Mn^2+(aq) + 8H2O (l) + 5S^2-(aq)
Thus the lowest smallest whole-number coefficient for H₂S is 5.
Learn more about redox reaction:brainly.com/question/13293425
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Answer:
591.25ml
Explanation:
4 cups=946ml
0.5cups=946÷8=118.25ml
2.5cups=118.25ml*5=591.25ml
Answer:
b. Each chlorine has three non-bonded pairs and one bonded pair of electrons.
Explanation:
Chlorine has three valance electrons. Each Cl atom forms a single covalent bond with the central P atom by sharing a pair of electrons. After forming a single covalent bond each Cl atom is left with six electrons that do not participate in any bond formation or there are three pairs of lone electrons.
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