Question

A chemist prepares a solution of calcium sulfate CaSO4 by measuring out 0.03g of calcium sulfate into a 150.mL volumetric flask and filling the flask to the mark with water. Calculate the concentration in /molL of the chemist's calcium sulfate solution. Be sure your answer has the correct number of significant digits.

Answer 1

Answer:

0.00147 Molar is the molarity of the solution.

Explanation:

Molarity of the solution is the moles of compound in 1 Liter solutions.

$Molarity=\frac{\text{Mass of compound}}{\text{Molar mas of compound}\times Volume (L)}$

Mass of calcium sulfate = 0.03 g

Molar mass of calcium sulfate = 136 g/mol

Volume of the calcium sulfate = 150. mL = 0.150 L ( 1 L = 0.001 mL)

$Molarity=\frac{0.03 g}{136 g/mol\times 0.150 L}=0.00147 mol/L$

0.00147 Molar is the molarity of the solution.