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Advocard [28]
3 years ago
9

. When 400 grams of wood are burned, 30 grams of ash remain. What happened to the missing 370 grams of matter?

Chemistry
1 answer:
tiny-mole [99]3 years ago
3 0
When wood id burnt, 30 grams of ash are formed due to the chemical changes that occurred.
The missing 370 grams are evaporated into the air where they form other particles and substances.
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Most of the dissolved substance in sea water is: hydrogen chloride nitrogen sodium ANSWER NOW! I NEED HELP ASAP! WILL GIVE BRAIN
VMariaS [17]

Answer: Sodium chloride

Explanation:

Ocean water contains a number of substances. When a substance which has ionic bonds is dissolved in water it takes the form of ions.

The most common ions in ocean water are sodium and chloride. These are the ions formed when common salt, sodium chloride (NaCl) is dissolved in water.

Sodium chloride accounts for about 3% of ocean water by mass.

3 0
3 years ago
The following is a procedure that was theoretically performed by a student. Read through the procedure and answer the questions
yKpoI14uk [10]

Answer:

CaCl2 (aq) + K2CO3(aq) ---------> CaCO3(s) + 2KCl(aq)

Explanation:

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CaCl2 (aq) + K2CO3(aq) ---------> CaCO3(s) + 2KCl(aq)

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6 0
3 years ago
If there are 40 mol of NBr3 and 48 mol of NaOH, what is the excess reactant
Vanyuwa [196]
<h3>Answer:</h3>

              Excess Reagent =  NBr₃

<h3>Solution:</h3>

The Balance Chemical Equation for the reaction of NBr₃ and NaOH is as follow,

                       2 NBr₃ + 3 NaOH   →   N₂ + 3 NaBr + 3 HBrO

Calculating the Limiting Reagent,

According to Balance equation,

               2 moles NBr₃ reacts with  =  3 moles of NaOH

So,

           40 moles of NBr₃ will react with  =  X moles of NaOH

Solving for X,

                       X  =  (40 mol × 3 mol) ÷ 2 mol

                       X  =  60 mol of NaOH

It means 40 moles of NBr₃ requires 60 moles of NaOH, while we are provided with 48 moles of NaOH which is Limited. Therefore, NaOH is the limiting reagent and will control the yield of products. And NBr₃ is in excess as some of it is left due to complete consumption of NaOH.

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