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Verdich [7]
4 years ago
12

A teacher describes a mathematical system that can be used to convert the weight of water to the mass of water. What is the teac

her most likely describing?
Chemistry
2 answers:
natali 33 [55]4 years ago
6 0
To describe a mathematical system that converts weight of water to mass equivalent, the teacher must use the idea of acceleration of gravity. Mass is the amount of matter composed in a substance. Weight is affected by the pull of gravity. Weight is mass multiplied by acceleration of gravity. Gravity acceleration is equal to 9.81 m/s2. So to convert weight to mass, divide the weight by 9.81 m/s2 simply.
VMariaS [17]4 years ago
6 0
She is most likely to find basically the weight and mass and what is the difference.
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Igneous intrusion D is younger than layers B, C, and E according to
Maurinko [17]

Answer:

Law of cross-cutting relationships

Explanation:

This interpretation is based on the law of cross - cutting relationships.

This law states that "faults and fractures that cuts through a rock are younger than the rocks they cut through".

  • In a sequence of strata, the strata that are not cut through by these features are younger than the cross -cutting features.
  • The igneous intrusion is younger since it cuts through the rock layers.
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3 years ago
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5 0
4 years ago
A scientist wants to make a solution of tribasic sodium phosphate, Na3PO4, for a laboratory experiment. How many grams of Na3PO4
san4es73 [151]

Answer:

83.20 g of Na3PO4

Explanation:

1 mole of Na3PO4 contains 3 moles of Na+.

Mole of Na ion to be prepared = Molarity x volume

                 = 0.700 x 725/1000

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If 1 mole of Na3PO4 contains 3 moles of Na ion, then 0.5075 Na ion will be contained in:

           0.5075/3 x 1 = 0.1692 mole of Na3PO4

mole of Na3PO4 = mass/molar mass = 0.1692

Hence, mass of Na3PO4 = 0.1692 x molar mass

                                     = 0.1692 x 163.94

                                        = 83.20 g.

83.20 g of Na3PO4 will be needed.

3 0
4 years ago
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Element R and Element Q have the same number of valence electrons. These elements have similar chemical behavior, but element R
I am Lyosha [343]

Answer:

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