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Slav-nsk [51]
2 years ago
10

The isomerization of methylisonitrile to acetonitrile CH3NC(g) → CH3CN(g) is first order in CH3NC. The rate constant for the rea

ction is 9.45 × 10-5 s-1 at 478 K. The half-life of the reaction when the initial [CH3NC] is 0.030 M is ________ s
Chemistry
1 answer:
Finger [1]2 years ago
6 0

Answer: The half-life of the reaction is 7333 seconds

Explanation:

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant

t = age of sample

a = let initial amount of the reactant

a - x = amount left after decay process  

a) for completion of half life:

Half life is the amount of time taken by a radioactive material to decay to half of its original value.

t_{\frac{1}{2}}=\frac{0.693}{k}

t_{\frac{1}{2}}=\frac{0.693}{9.45\times 10^{-5}}=7333s

The half-life of the reaction is 7333 seconds

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Answer:

"The elements are arranged in seven horizontal rows,called periods or series,and 18 vertical columns,called Groups."

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Using the redox reaction below determine which element is oxidized and which is reduced. 4nh3 + 3ca(clo)2 → 2n2 + 6h2o + 3cacl2
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The oxidation number of elements in equation below are,

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O.N of N in NH₃ = -3
O.N of Ca in Ca(ClO)₂ and CaCl₂ = +2
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Reduction:
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Result:
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6 0
3 years ago
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Consider this reaction: HCO3− + H2S → H2CO3 + HS− Which is the Bronsted-Lowry base? H2S HCO3- HS– H2CO3
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3 0
3 years ago
Copper(II) fluoride contains 37.42% F by mass. Calculate the mass of fluorine (in g) in 55.5 g of copper(II) fluoride.
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Answer:

There are 20.8 g of fluorine in 55.5 g of copper (II) fluoride

Explanation:

x % by mass of a species in a specimen means there are x g of the species in total 100 g of a specimen

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So, 100 g of copper (II) fluoride contains 37.42 g of F

55.5 g of copper (II) fluoride contains \frac{37.42\times 55.5}{100}g of F or 20.8 g of F

Hence there are 20.8 g of fluorine in 55.5 g of copper (II) fluoride.

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3 years ago
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