Answer:
Ethanol = 102.29 g
Carbon Dioxide = 97.71 g
Solution:
The Balance Chemical Equation for the fermentation of Glucose is as follow,
C₆H₁₂O₆ → 2 C₂H₅OH + 2 CO₂
Mass of Ethanol produced:
According to equation;
180.156 g (1 mole) C₆H₁₂O₆ produces = 92.14 g (2 moles) of C₂H₅OH
So,
200 g of C₆H₁₂O₆ will produces = X g of C₂H₅OH
Solving for X,
X = (200 g × 92.14 g) ÷ 180.156 g
X = 102.29 g of C₂H₅OH
Mass of Carbon Dioxide produced:
According to equation;
180.156 g (1 mole) C₆H₁₂O₆ produces = 88.02 g (2 moles) of CO₂
So,
200 g of C₆H₁₂O₆ will produces = X g of CO₂
Solving for X,
X = (200 g × 88.02 g) ÷ 180.156 g
X = 97.71 g of CO₂
Answer:
The temperature at which each bean is kept
Explanation:
Independent variable is what YOU CHANGE
Answer:
118.75°C is the boiling point of a solution.
Explanation:
Mass of the solute that is barbiturates = 42.5 g
Molar mass of a solute = 184.2 g/mol
Moles of solute =
Mass of the solvent that acetic acid = 825 g = 0.825 kg
Molality of the solution (m):
Elevation in boiling point is given as:
i = 1 (organic compound)
= Boiling temperature of solution.
T = boiling temperature of solvent that is acetic acid=117.9°C
118.75°C is the boiling point of a solution.
Explanation:
The kilometre (SI symbol: km; /ˈkɪləmiːtər/ or /kɪˈlɒmɪtər/), spelt kilometer in American English, is a unit of length in the metric system, equal to one thousand metres (kilo- being the SI prefix for 1000).