Explanation:
The balanced equation of the reaction is given as;
Mg(OH)2 (s) + 2 HBr (aq) → MgBr2 (aq) + 2 H2O (l)
1. How many grams of MgBr2 will be produced from 18.3 grams of HBr?
From the reaction;
2 mol of HBr produces 1 mol of MgBr2
Converting to masses using;
Mass = Number of moles * Molar mass
Molar mass of HBr = 80.91 g/mol
Molar mass of MgBr2 = 184.113 g/mol
This means;
(2 * 80.91 = 161.82g) of HBr produces (1 * 184.113 = 184.113g) MgBr2
18.3g would produce x
161.82 = 184.113
18.3 = x
x = (184.113 * 18.3 ) / 161.82 = 20.8 g
2. How many moles of H2O will be produced from 18.3 grams of HBr?
Converting the mass to mol;
Number of moles = Mass / Molar mass = 18.3 / 80.91 = 0.226 mol
From the reaction;
2 mol of HBr produces 2 mol of H2O
0.226 mol would produce x
2 =2
0.226 = x
x = 0.226 * 2 / 2 = 0.226 mol
3. How many grams of Mg(OH)2 are needed to completely react with 18.3 grams of HBr?
From the reaction;
2 mol of HBr reacts with 1 mol of Mg(OH)2
18.3g of HBr = 0.226 mol
2 = 1
0.226 = x
x = 0.226 * 1 /2
x = 0.113 mol
<u>Answer:</u> The change in internal energy of the gas is 108.835 kJ
<u>Explanation:</u>
To calculate the work done for reversible expansion process, we use the equation:
where,
W = work done
P = pressure = 1.03 atm
= initial volume = 3.00 L
= final volume = 11.0 L
Putting values in above equation, we get:
(Conversion factor: 1 L. atm = 101.325 J)
Calculating the heat from power:
where,
Q = heat required
P = power = 150 W
t = time = 12 min = 720 s (Conversion factor: 1 min = 60 s)
Putting values in above equation:
The equation for first law of thermodynamics follows:
where,
Q = total amount of heat required = 108 kJ
dU = Change in internal energy = ?
W = work done = -0.835 kJ
Putting values in above equation, we get:
Hence, the change in internal energy of the gas is 108.835 kJ
its 640 because 150 goes into 900 6.4 times do you multiply 6.4 and 100 which is 640.
Answer:
B) Crust
Explanation:
It's the farthest layer from the core listed.
