Answer:
Figure 1 provides the rawest and most accurate data.
Explanation:
Answer: The molality of solution is 17.6 mole/kg
Explanation:
Molality of a solution is defined as the number of moles of solute dissolved per kg of the solvent.
where,
n = moles of solute
= weight of solvent in kg
moles of acetone (solute) = 0.241
moles of water (solvent )= (1-0.241) = 0.759
mass of water (solvent )= 
Now put all the given values in the formula of molality, we get
Therefore, the molality of solution is 17.6 mole/kg
Answer:
165.5 g of CO2
Explanation:
We must first put down the balanced reaction equation:
C4H10(g) + 13/2 O2(g) ------> 4CO2(g) + 5H2O(g)
From the reaction equation, one mole of butane occupies 22.4 L hence we can establish the stoichiometry of the reaction thus:
22.4 L of butane created 174 g of CO2
Therefore 21.3 L of butane will create 21.3 × 174/22.4 = 165.5 g of CO2
Answer:
<h2>Here is the correct answer </h2>
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and development of the following layers lethargic
Explanation:
STUDY CORRECTION.
Answer:
547.5g
Explanation:
To get the mass, you need moles.
moles = (molarity)(Liters)
moles = (1.230M)(4.200L) = 5.166 moles Na2CO3
Now, just use stoichiometry
molar mass of Na2CO3 = 2(mass of Na) + (mass of C) + 3(mass of O)
= 2(22.9) + 12.01 + 3(16) = 105.99g/mol
5.166moles(105.99g/mol)
= 547.544
But, the measurements given had 4 significant figures, so in chemistry we write:
547.5g
