Which statement is always true about a reversible chemical reaction?

Chemistry

1 answer:

Alecsey [184]3 years ago

7 0

<h2>Answer:</h2>

Option (B):

The products can form reactants, and the reactants can form products.

<h3>Explanation:</h3><h3>Reversible reaction</h3>

A reversible reaction is a reaction where the reactants form products, which react together to give the reactants back.

aA + bB ⇄ cC + dD

A and B can react to form C and D or, in the reverse reaction, C and D can react to form A and B.

Other options are wrong because off:

(A) Concentration changes with time equilibrium concentration and higher product concentration is also possible.

(C) They may be constant.

(D) Concentration changes with time equilibrium concentration and higher reactant concentration is also possible.

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Fill in the left side of this equilibrium constant equation for the reaction of benzoic acid (HC_6H_5CO_2) with water.

il63 [147K]

Answer:

[C₆H₅COO⁻][H₃O⁺]/[C₆H₅COOH] = Ka

Explanation:

The reaction of dissociation of the benzoic acid in water is given by the following equation:

C₆H₅-COOH + H₂O ⇄ C₆H₅-COO⁻ + H₃O⁺ (1)

The dissociation constant of an acid is the measure of the strength of an acid:

HA ⇄ A⁻ + H⁺ (2)

$K_{a} = \frac{[A^{-}][H^{+}]}{[HA]}$ (3)

<em>Where the dissociation constant of the acid (Ka) is equal to the ratio of the concentration of the dissociated forms of the acid, [A⁻][H⁺], and the concentration of the acid, [HA]. </em>

So, starting from the equations (2) and (3), the constant equation for the dissociation reaction of benzoic acid in water, of the equation (1), is:

$K_{a} = \frac{[C_{6}H_{5}COO^{-}][H_{3}O^{+}]}{[C_{6}H_{5}COOH]}$