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Anna [14]
3 years ago
15

What mass of methane (CH4) gas occupies a volume of 0,462 L at 1atm and 273K

Chemistry
1 answer:
LiRa [457]3 years ago
6 0

Explanation:

Since methane gas is at 1 atm and 273 K, it is at standard temperature and pressure(STP).

One mole of every gas occupies 22.4 dm^3 at STP, and vice versa. So,

22.4 dm^3 at STP of CH4=1 mol=12+4(1)=16 g

0.462 L(0.462 dm^3) at STP of CH4

=(16 g×0.462 dm^3)/22.4 dm^3

=0.33 g

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Answer:

to validate the law of conservation of mass as total no. of reactants must be equal to the total no. of products

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3 years ago
A sample of oxygen gas has a volume of 45.8 mL when its pressure is 0.492 atm. What
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Answer:

<h2> a. 23.6</h2>

Explanation:

P_1=0.492\:atm\\V_1 = 45.8\:ml\\V_2 = ?\\P_1 = 0.954\:atm\\\\Boyle's Law = P_1V_1 = P_2V_2\\\\Lets \:make\: V \:subject\:of\:the\:formula\\\\\frac{P_1V_1}{P_2} = \frac{P_2V_2}{P_2} \\ \\V_2 =\frac{P_1V_1}{P_2} \\V_2 = \frac{0.492\times45.8}{0.954}\\ \\V_2 = \frac{22.5336}{0.954} \\\\V_2  = 23.620\\\\V_2 = 23.6

4 0
3 years ago
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A solution is made by mixing equal masses of methanol, CH 4 O , and ethanol, C 2 H 6 O . Determine the mole fraction of each com
Fynjy0 [20]

Answer:

Mole fraction of CH_4O = 0.58

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The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

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Moles_{CH_4O}= \frac{x\ g}{33.035\ g/mol}

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Mole\ fraction\ of\ CH_4O=\frac {n_{CH_4O}}{n_{CH_4O}+n_{C_2H_6O}}

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3 years ago
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torisob [31]

Answer:

in the middle

Explanation:

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