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3 years ago

What is the domain of this graph?

Mathematics

1 answer:

Salsk061 [2.6K]3 years ago

5 0

$\rm{\pink{\underline{\underline{\blue{TO\:FIND:-}}}}}$

The domain of the attachment graph .

$\rm{\pink{\underline{\underline{\blue{SOLUTION:-}}}}}$

The method to identify the domain and range of functions is by using graphs :-

⚡ The domain refers to the set of possible input values, the domain of a graph consists of all the input values shown on the x-axis .

⚡ The range is the set of possible output values, which are shown on the y-axis .

See the attachment figure .

[NOTE :- Keep in mind that if the graph continues beyond the portion of the graph we can see, the domain and range may be greater than the visible values .]

✍️ So, we can observe that the graph extends horizontally from -3 to the right with +10 .

✯ Hence, the domain is [-3 , 10] .

You might be interested in

What is the equation of this graphed line?

barxatty [35]

Answer:

$y=-\frac{1}{3}x-5$

Step-by-step explanation:

Given:

The two points on the line are:

$(x_1,y_1)=(-6,-3)\\(x_2,y_2)=(6,-7)$

Now, for a line with two points on it, the slope of the line is given as:

$m=\frac{y_2-y_1}{x_2-x_1}$

For the points $(x_1,y_1)=(-6,-3)\ and\ (x_2,y_2)=(6,-7)$ , slope is:

$m=\frac{-7-(-3)}{6-(-6)}\\m=\frac{-7+3}{6+6}\\m=\frac{-4}{12}=-\frac{1}{3}$

Now, for a line with slope 'm' and a point $(x_1,y_1)$ on it is given as:

$y-y_1=m(x-x_1)$

Plug in all the values and determine the equation of the line. This gives,

$y-(-3)=-\frac{1}{3}(x-(-6))\\\\y+3=-\frac{1}{3}(x+6)\\\\y+3=-\frac{1}{3}x-\frac{1}{3}\times 6\\\\y+3=-\frac{1}{3}x-2\\\\y=-\frac{1}{3}x-2-3\\\\y=-\frac{1}{3}x-5$

Therefore, the equation of the line is:

$y=-\frac{1}{3}x-5$

4 0

3 years ago

What is the average cost of 7 articles if 3 of them cost 30k each and the rest cost 12.5k each

LenKa [72]

${\bold{\red{\huge{\mathbb{QUESTION}}}}}$

what is the average cost of 7 articles if 3 of them cost 30k each and the rest cost 12.5k each

$\bold{ \red{\star{\blue{GIVEN }}}}$

TOTAL NUMBER OF ARTICLE= 7

ARTICLES FOR 30K = 3

ARTICLES FOR 12.5K = 7-3= 4

$\bold{\blue{\star{\red{TO \: \: FIND}}}}$

Average cost of 7 articles

$\bold{ \green{ \star{ \orange{FORMULA \: USED}}}}$

$\red{AVERAGE = \frac{TOTAL \: COST}{ NUMBER \: OF\: ARTICLES }}$

$\huge\mathbb{\red A \pink{N}\purple{S} \blue{W} \orange{ER}}$

$Average \: cost \: of \: 7 \: articles - > \\ \frac{(3 \times 30k) + (12 .5k \times 4)}{7} \\ \frac{90k + 50k}{7} \\ \frac{140k}{7} \\ \blue {Average \: cost \: of \: 7 \: articles - >} \\ 20k$