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Nimfa-mama [501]
3 years ago
15

As a freely falling object picks up downward speed, what happens to the power supplied by the gravitational force?

Physics
1 answer:
vitfil [10]3 years ago
4 0

We will start from the definition of power in terms of the Force. Power could be described as the change of energy in an instant of time. Considering that Energy is the product between the Force and the distance traveled we would arrive at the expression

P = \frac{E}{t}

P = \frac{F*h}{t}

Here,

F = Force

h = Height

t = Time

As there is no external force, apart from the force of gravity, and this, is constant during the course of the object we will also have to be constant power and therefore this during its course will be the same. The correct answer is (1)

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1.How far is Object Z from the origin at t = 3 seconds?
GenaCL600 [577]

Answer:

Please find the answer in the explanation

Explanation:

1.) How far is Object Z from the origin at t = 3 seconds

The distance of the object Z from the origin will be the slope of the graph.

Slope = 4/2 = 2m

2.) Which object takes the least time to reach a position 4 meters from the origin ?

According to the graph given to the question above, object Z has the list time which is 2 seconds since object X does not start from the origin.

3.) Which object is farthest from the origin at t = 2 seconds?

The correct answer is still object Z because it has the highest slope.

4 0
2 years ago
Sound waves have relatively long wavelengths. We can hear people around the corner before we can see them. Which wave behavior d
pogonyaev
I'd say diffraction since sound waves can bend around objects like corners. Let's say you're in the hallway and you can hear sound coming from a door. The sound waves diffract around the door and spread out into the hallway, making it possible for you to hear.  
Also, you can hear it before you see it because light waves are shorter than sound waves and hardly diffract around doors. 
6 0
2 years ago
A Styrofoam ball has just been shot straight up. Air resistance is not negligible (free body diagram)
timofeeve [1]

In a free body diagram for an object projected upwards;

  • the acceleration due to gravity on the object is always directed downwards.
  • the velocity of the object is always in the direction of the object's motion.

An object projected upwards is subjected to influence of acceleration due to gravity.

As the object accelerates upwards, its velocity decreases until the object reaches maximum height where its velocity becomes zero and as the object descends its velocity increases, which eventually becomes maximum before the object hits the ground.

To construct a free body diagram for this motion, we consider the following;

  • the acceleration due to gravity on the object is always directed downwards
  • the velocity of the object is always in the direction of the object's motion.

<u>For instance:</u>

upward motion for velocity  ↑        downward motion for velocity  ↓

                                              ↑                                                            ↓

                                              ↑                                                            ↓

acceleration due to gravity ↓

                                             ↓

                                             ↓

Learn more here: brainly.com/question/13235430

5 0
2 years ago
a uniform rule balance on a knife edge at the 55cm mark when a mass of 40g is hung from the 95cm mark. find the weight of the ru
BigorU [14]

Answer:

W = 3.1 N

Explanation:

moments about any convenient point will sum to zero.

I choose summing about the knife edge mark and will assume the ruler of weight W is of uniform construction.

I will assume the ruler weight makes a positive moment

W[55 - 50) - 0.040(9.8)[ 95 - 55] = 0

                                                5W = 15.68

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7 0
2 years ago
g A 2.3 kg block is attached to the spring, and it is released from rest 0.7 m from the spring's equilibrium position. Neglectin
DedPeter [7]

Answer:

3.71 m/s

Explanation:

From the law of conservation of linear momentum, since we are neglecting minor energy losses due to friction then we can express it as mgh=0.5mv^{2} since all the potential energy is transformed to kinetic energy

Making v the subject of the formula then v=\sqrt {2gh} and here m is the mass of the block, g is acceleration due to gravity, h is the height. Substituting 0.7 m for h and 9.81 for g then we obtain that v=\sqrt {2\times 9.81\times 0.7}=3.705941176 m/s\approx 3.71 m/s

6 0
3 years ago
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