Answer:
If the speed of the merry-go-round doubles, the force you will need to exert to hang on is 400 N.
Explanation:
Given;
initial force exerted to hang on, F₁ = 100 N
The force exerted on the merry-go-round in order to hang on must be an inward force known as centripetal force.
Centripetal force is given by;
Therefore, If the speed of the merry-go-round doubles, the force you will need to exert to hang on is 400 N.
<u>Answer:</u>
Speed of Hawk's shadow on the level ground = 3.29 m/s
<u>Explanation:</u>
When the sun is directly above the head of hawk shadow will be directly below hawk. So the speed of hawk's shadow will be equal to speed of hawk's in X -direction.
Velocity of hawk = 5.35 m/s
Angle from horizontal = 52.00⁰
Horizontal component = 5.35 cos 52.00⁰ = 3.29 m/s
So speed of hawk's shadow = 3.29 m/s
If a simple machine reduces the strength of a force, "<span>the distance over which the force is applied" must be increased in order to keep the work constant.
In short, Your Answer would be Option A
Hope this helps!</span>
Answer:
D
Explanation:
LA FUERZA NETA ES LA FUERZA TOTAL DE EMPUJE MENOS EL PESO DEL
COHETE.
= 700000 N(sen 90° - 20°) - 560000 N = 97785 N
Answer and Explanation: When tossing a ball up in the air, the forces acting on the ball are due to Gravity, which is defined by gravitational acceleration on that location on Earth (approximately 9.8 m/s²) multiplied by mass of the ball; Force of thrown, i.e., the force you threw the ball and air resistance force, which is proportional to the square of the ball's through the air and the ball's cross section area. To facilite calculations, air resistance force is normally ignored.