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vazorg [7]
3 years ago
7

Complete this sentence. If mass remains the same while the volume of a substance ________, the density of the substance will____

___________. decreases, decrease increases, decrease increases, stay the same decreases, stay the same
Physics
2 answers:
Natasha_Volkova [10]3 years ago
7 0

Answer:

increases, decrease

Explanation:

The density of a body is the measure of mass concentration of a material. It is an intrinsic property which is constant. It is the ratio of mass and volume

m = Mass

v = Volume

Density

\rho=\frac{m}{v}

This means that density is inversely proportional to volume.

So, if volume increases density will decrease.

MariettaO [177]3 years ago
5 0
If mass remains the same while the volume increases, the density of the substance will decrease.
If mass remains the same while the volume decreases, the density of the substance will increase.
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Answer:

357KG

Explanation:

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Find the work done in pumping gasoline that weighs 6600 newtons per cubic meter. A cylindrical gasoline tank 3 meters in diamete
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Answer:

<em>work done in pumping the entire fuel is 466587 J</em>

<em></em>

Explanation:

weight of the gasoline per volume = 6600 N/m^3

diameter of the tank = 3 m

length of the tank = 2 m

height of the tractor tank above the top of the tank = 5 m

work done in pumping fuel to this height = ?

First, we find the volume of the fuel

since the tank is cylindrical,<em> we assume that the fuel within also takes the cylindrical shape.</em>

<em>Also, we assume that the fuel completely fills the tank.</em>

volume of a cylinder = \pi r^{2}l

where r = radius = diameter ÷ 2 = 3/2 = 1.5 m

volume of the cylinder = 3.142 x 1.5^{2} x 2 = 14.139 m^3

we then find the total weight of the fuel in Newton

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total weight = 6600 x 14.139 = 93317.4 N

work done = (total weight of the fuel) x (height through which the fuel is pumped)

work done in pumping = 93317.4 x 5 = <em>466587 J</em>

8 0
3 years ago
If Mars were 10 times closer to the Sun, then the Sun would attract Mars with
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3 years ago
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A 20 m high filled water tank develops a 0.50 cm hole in the vertical wall near the base. With what speed does the water shoot o
Rina8888 [55]

Answer:

The speed of the water shoot out of the hole is 20 m/s.

(d) is correct option.

Explanation:

Given that,

Height = 20 m

We need to calculate the velocity

Using formula Bernoulli equation

\dfrac{1}{2}\rho v_{1}^2+\rho gh_{1}=\dfrac{1}{2}\rho v_{2}^2+\rho gh_{2}

Where,

v₁= initial velocity

v₂=final velocity

h₁=total height

h₂=height of the hole from the base

Put the value into the formula

v_{1}^2=2g(h_{2}-h_{1})

v_{1}=\sqrt{2g(h_{2}-h_{1})}

v_{1}=\sqrt{2\times9.8\times(20-0.005)}

v_{1}=19.7\ m/s= approximate\ 20\ m/s

Hence, The speed of the water shoot out of the hole is 20 m/s.

7 0
3 years ago
During an adiabatic process an object does 100 J of work and its temperature decreases by 5 K. During another process it does 25
Liono4ka [1.6K]

Answer:

The heat capacity for the second process is 15 J/K.

Explanation:

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nC_{v}=\dfrac{dU}{dT}

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Put the value into the formula

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We need to calculate the heat capacity for the second process

Using formula of heat

dQ=nC_{v}(dT_{1})

Put the value into the formula

-75=nC_{v}\times(-5)

nC_{v}=\dfrac{-75}{-5}

nC_{v}=15\ J/K

Hence, The heat capacity for the second process is 15 J/K.

5 0
3 years ago
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