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vazorg [7]
3 years ago
7

Complete this sentence. If mass remains the same while the volume of a substance ________, the density of the substance will____

___________. decreases, decrease increases, decrease increases, stay the same decreases, stay the same
Physics
2 answers:
Natasha_Volkova [10]3 years ago
7 0

Answer:

increases, decrease

Explanation:

The density of a body is the measure of mass concentration of a material. It is an intrinsic property which is constant. It is the ratio of mass and volume

m = Mass

v = Volume

Density

\rho=\frac{m}{v}

This means that density is inversely proportional to volume.

So, if volume increases density will decrease.

MariettaO [177]3 years ago
5 0
If mass remains the same while the volume increases, the density of the substance will decrease.
If mass remains the same while the volume decreases, the density of the substance will increase.
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What is the maximum number of lines per centimeter a diffraction grating can have and produce a complete first-order spectrum fo
Pachacha [2.7K]

Answer:

14,300 lines per cm

Explanation:

Answer:

14,300 cm per line

Explanation:

λ400 nm to 400nm

We can find the maximum number of lines per centimeter, which is reciprocal of the least distance separating two adjacent slits, using the following equation.

mλ = dsin (θ)

In this equation,

m is the order of diffraction.

λ is the wavelength of the incident light.

d is the distance separating the centers of the two slits.

θ is the angle at which the mth order would diffract.

To find the least separation that allows the observation of one complete order of spectrum of the visible region, we use the maximum wavelength of the visible region is 700 nm.

d =  mλ / sin (θ)

As we want the distance d to be the smallest then sin (θ) must be the greatest, and the greatest value of the sin (θ) is 1. For that we also use the longest wavelength because using the smallest wavelength, the longest wavelength would not be diffracted.

d =  mλ / sin (θ)

d =  1 x 700nm / 1

  = 700 nm

So, the least separation that would allow for the possibility of observing complete first order of the visible region spectra is 700 nm, and knowing the least separation we can find the maximum number of lines per cm, which is the reciprocal of the number of lines per cm.

n = 1/d

   = 1 / 700 x 10^{-9}

  = 1, 430,000 lines per m  

  =  14,300 lines per cm

<u>The maximum number of lines per cm, that would allow for the observation of the complete first order visible spectra.</u>

5 0
3 years ago
A car changes chemical energy from fuel into thermal energy and ________ energy.
Shkiper50 [21]

Answer:

Mechanical energy

Explanation:

A car changes chemical energy from fuel into thermal energy and mechanical energy.

Mechanical energy can be defined as the type of energy that is possessed by an object due to its motion or position. Mechanical energy is the sum of potential energy and kinetic energy, that is, the sum of energy in motion and stored energy. Examples of mechanical energy includes driving a car, riding a bicycle, listening to music etc.

Types of mechanical energy

1. Motion energy (kinetic energy)

2. Stored energy(potential energy)

Mechanical energy = Kinetic energy + Potential energy

4 0
3 years ago
What is the resistance of a conductor
Ivenika [448]

Opposition for the current flow

Explanation:

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  • Resistance is an important parameter in a circuit design and it should be properly designed.
  • Resistance of a conductor depends upon the material nature, length of the conductor and area of cross section.
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3 years ago
A long, hollow wire with inner radius a and outer radius b carries a uniform current density J. What is the magnetic field as a
sveta [45]

Answer:

The magnetic field in the region a < r < b is B=\frac{u_{0}I(r^{2}-a^{2})   }{2\pi r(b^{2}-a^{2})  }

Explanation:

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J=\frac{I_{total} }{A}

Where:

A = area enclosed by the loop.

Itotal = total current in loop.

J=\frac{I}{\pi b^{2}-\pi  a^{2} }

I_{enclosed} =JA_{enclosed}

I_{enclosed} =\frac{I(\pi r^{2}- \pi a^{2})}{\pi b^{2}-\pi a^{2}  }

If we have the Ampere`s law:

\int\limits^a_b {B} \, ds  =u_{0} I_{enclosed} \\2B\pi r=u_{0} (\frac{I(\pi r^{2}-\pi  ^{2} }{\pi ^{2}-\pi  a^{2} } )\\B=\frac{u_{0}I(r^{2}-a^{2})   }{2\pi r(b^{2}-a^{2})  }

6 0
3 years ago
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