![\\ \bull\tt\longrightarrow P=\dfrac{V^2}{R}](https://tex.z-dn.net/?f=%5C%5C%20%5Cbull%5Ctt%5Clongrightarrow%20P%3D%5Cdfrac%7BV%5E2%7D%7BR%7D)
- P is power
- R is resistance
![\\ \bull\tt\longrightarrow R=\dfrac{V^2}{P}](https://tex.z-dn.net/?f=%5C%5C%20%5Cbull%5Ctt%5Clongrightarrow%20R%3D%5Cdfrac%7BV%5E2%7D%7BP%7D)
Hence
![\\ \bull\tt\longrightarrow R\propto V](https://tex.z-dn.net/?f=%5C%5C%20%5Cbull%5Ctt%5Clongrightarrow%20R%5Cpropto%20V)
![\\ \bull\tt\longrightarrow R\propto \dfrac{1}{P}](https://tex.z-dn.net/?f=%5C%5C%20%5Cbull%5Ctt%5Clongrightarrow%20R%5Cpropto%20%5Cdfrac%7B1%7D%7BP%7D)
- Therefore if power is low then resistance will be high.
The first bulb has less power hence it has greater filament resistance.
Any process in which a mixture of materials separates out partially
Answer:
Only option A is correct
Explanation:
From the concept of Doppler effect, only speed matters. Thus, the faster a vehicle is moving, the closer together the sound waves get compressed and the higher the frequency. For example, for a very fast vehicle traveling at the speed of sound; the compressions are all right on top of each other. Thus, faster speed means closer compressions and higher frequencies. Hence, option only option A must be true because X is a higher frequency and so it must be going faster. The distance to the person will affect the volume but will not the pitch so Option B is not correct. Option C too is not correct because It doesn’t matter whether you are speeding up or slowing down, it only matters who is going faster. For example, from option c concept, if truck X was going 10 m/h and speeding up while truck Y was going 50 mph and slowing down, it would not meet the requirement that X has a higher frequency because only actual speed matters, not what is happening to that speed. Thus only option A is the correct answer
Answer:
<em>2.72 x 10^-43 m</em>
<em></em>
Explanation:
mass of the telescope = 7500 kg
speed of the telescope = 3.25 x 10^5 m/s
de Broglie's wavelength of the telescope is given as
λ = h/mv
where
λ is the wavelength of the telescope
h is the plank's constant = 6.63 × 10-34 m^2 kg/s
m is the mass of the telescope = 7500 kg
v is speed of the telescope = 3.25 x 10^5 m/s
substituting value, we have
λ = (6.63 × 10-34)/(7500 x 3.25 x 10^5)
λ = <em>2.72 x 10^-43 m</em>