2 years ago

a radioactive tracer has a half-life of 2 hours. how much of a 2500g sample will be avalible after 18 hours

Physics

1 answer:

zhannawk [14.2K]2 years ago

8 0

Answer:

i believe the answer is 2.44140625 grams remaining

You might be interested in

Charlotte is driving at 66.5 mi/h and receives a text message. She looks down at her phone and takes her eyes off the road for 3

Alborosie

Answer:

the distance traveled by Charlotte in feet is 338.44 ft

Explanation:

Given;

speed of Charlotte, u = 66.5 mi/h

time of motion, t = 3.47 s

The distance traveled by Charlotte in feet is calculated as;

$Distance = Speed \ \times \ time \\\\D = ut\\\\D = (\frac{66.5 \ mi}{h} \times \frac{5280 \ ft}{1 \ mi} \times \frac{1 \ h}{3600 \ s} )(3.47 \ s)\\\\D = 338.44 \ ft$

Therefore, the distance traveled by Charlotte in feet is 338.44 ft

7 0

2 years ago

One who voluntarily donates tissues/ organs striped

Artist 52 [7]

A tissue donor is what you're probably looking for. :)

8 0

3 years ago

Under state law, what is the blood-alcohol limit for legally operating a motor vehicle?

Ymorist [56]

Answer:

HOPE IT HELPS....

Explanation:

CORRECT ANSWER IS 0.08

THANK YOU,

PLZ MARK ME AS BRAINLIST

5 0

2 years ago

True or false it is impossible to determine weather you are moving unless you can touch another object

Lerok [7]

Answer: false

Explanation:

4 0

2 years ago

Read 2 more answers

A 300 g glass thermometer initially at 23 ◦C is put into 236 cm3 of hot water at 87 ◦C. Find the final temperature of the thermo

DIA [1.3K]

Answer:

$74^{\circ} C$

Explanation:

We are given that

Mass of glass, $m=300 g$

$T_1=23^{\circ}$

Volume, $V=236cm^3$

Mass of water= $density\times volume=1\times 236=236 g$

Density of water= $1g/cm^3$

Temperature of hot water, $T=87^{\circ}$

Specific heat of glass, $C_g=0.2cal/g^{\circ}C$

Specific heat of water, $C_w=1 cal/g^{\circ}C$

$Q_{glass}=m_gC_g(T_f-T_1)=300\times 0.2(T_f-23)$

$Q_{water}=m_wC_w(T_f-T)=236\times 1(T_f-87)$

$Q_{glass}+Q_{water}=0$

$300\times 0.2(T_f-23)+236\times 1(T_f-87)$

$60T_f-1380+236T_f-20532=0$

$296T_f=20532+1380=21912$

$T_f=\frac{21912}{296}=74^{\circ} C$

5 0

2 years ago