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3 years ago

13

Add. (2x² – 2x) + (6x-4)

1 answer:

algol [13]3 years ago

4 0

I believe it’s =52 or just 52

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If f(x)= 3/x+2- square root x-3, complete the following statement: f(19)=

I am Lyosha [343]

f(7)≈1.6666 Please mark me as brainliest

round

f(7)=1.67

The domain of the function is the set of all the values of x that would allow the function to have real values. Since the radicand is x - 3, the value of x cannot be less than 3 because that would make the value of sqrt (x - 3) an imaginary number. Thus, the domain should be all numbers GREATER than or equal to 3.

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If the temperature was -4 yesterday and 23 today what is the change in temperature

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27 degrees add four then 23 and you get 27

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Find all the zeros of the equation

lapo4ka [179]

Divide both sides by -3, and replace $x^2$ with $y$ . Then

$-3x^4+27x^2+1200=0\iff y^2-9y-400=0$

Factorize the quadratic in $y$ to get

$y^2-9y-400=(y+16)(y-25)=0\implies y=-16,y=25$

which in turn means

$x^2=-16,x^2=25$

But $x^2\ge0$ for all real $x$ , so we can ignore the first solution. This leaves us with

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4 years ago

Hellllllllllllllllllllllllllp

murzikaleks [220]

Answer:

$\begin{cases}y=-5x+1\\y=5x-4 \end{cases}$

Step-by-step explanation:

Slope-intercept form of a <u>linear equation</u>:

$\boxed{y=mx+b}$

where:

m is the slope.
b is the y-intercept (where the line crosses the y-axis).

<u>Slope formula</u>

$\boxed{\textsf{slope}\:(m)=\dfrac{y_2-y_1}{x_2-x_1}}$

<u>Equation 1</u>

<u />

Define two points on the line:

$\textsf{Let }(x_1,y_1)=(-1, 6)$

$\textsf{Let }(x_2,y_2)=(0, 1)$

<u>Substitute</u> the defined points into the slope formula:

$\implies \textsf{slope}\:(m)=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{1-6}{0-(-1)}=-5$

From inspection of the graph, the line crosses the y-axis at y = 1 and so the y-intercept is 1.

Substitute the found slope and y-intercept into the slope-intercept formula to create an equation for the line:

$y=-5x+1$

<u>Equation 2</u>

<u />

Define two points on the line:

$\textsf{Let }(x_1,y_1)=(1, 1)$

$\textsf{Let }(x_2,y_2)=(0, -4)$

<u>Substitute</u> the defined points into the slope formula:

$\implies \textsf{slope}\:(m)=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{-4-1}{0-1}=5$

From inspection of the graph, the line crosses the y-axis at y = -4 and so the y-intercept is -4.

Substitute the found slope and y-intercept into the slope-intercept formula to create an equation for the line:

$y=5x-4$

<u>Conclusion</u>

Therefore, the system of linear equations shown by the graph is:

$\begin{cases}y=-5x+1\\y=5x-4 \end{cases}$

Learn more about systems of linear equations here:

brainly.com/question/28164947

brainly.com/question/28093918

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